如何使用RegEx匹配以空格分隔的字符组？

Question

我使用下面的RegEx来确定某个字符串是否用AND或OR分隔

\W(:?AND|OR)\

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示例

Input:  ~abc[0|1] AND foo
Output: Match

Input:  ~secopssc{1,3} AND ~abc_d{3,4}
Output: Match

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类似地，我想编写一个正则表达式，使其匹配所有仅用空格而不用AND或OR分隔的字符串。

我尝试了以下RegEx：

^(?=.*\w\W+\w)(?:[\w ](?!\W(AND|OR)\W))+$

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这在以下位置提供了正确的输出：

Input:  foo bar
Output: Match
// This is correct since "foo" and "bar" are separated by a space

Input:  foo
Output: No Match
// This is correct since nothing is separated by a space

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但是在以下位置输出错误：

Input:  ~abc[0|1] foo
Output: No Match
// This is incorrect as both strings are separated by a space

Input:  ~secopssc{1,3} AND ~abc_d{3,4}
Output: No match
// This is incorrect as both strings are separated by a space

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总结：一种检查长字符串是否仅由仅由空格分隔的字符组组成的方法。

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有效字符串的示例：

foo{1,3} acb[1-2] a foo bar bar(qwer|qwyr)

（由于每个字符块之间都有空格，因此有效）

Answer 1

这解决了我的问题：

k = "foo{1,3} acb[1-2] AND a foo bar bar(qwer|qwyr)"
if not re.search(r'\W(:?AND|OR)\W', k) and k.strip().find(" ")!=-1:
      print "not separated by AND and OR but by space"
else:
      print "separated by AND/OR"