Question

我首先发送的那个参数就是被利用的那个。其余的将被忽略。如果您查看下面的分页信息，您将看到如何播放。为什么gitlab api V4仅尊重第一个参数，而忽略其余参数？

$ curl --head --header "PRIVATE-TOKEN: asdfasdf" https://gitlab.asdfasdf.com/api/v4/projects/?per_page=100&page=2

RESPONSE HEADERS
x-next-page: 2
x-page: 1
x-per-page: 100
x-prev-page:
x-total: 172
x-total-pages: 2


$ curl --head --header "PRIVATE-TOKEN: asdfasdf" https://gitlab.asdfasdf.com/api/v4/projects/?per_page=50&page=2

RESPONSE HEADERS
x-next-page: 2
x-page: 1
x-per-page: 50
x-prev-page: 
x-total: 172
x-total-pages: 4


$ curl --head --header "PRIVATE-TOKEN: asdfasdf" https://gitlab.asdfasdf.com/api/v4/projects?page=2

RESPONSE HEADERS
x-next-page: 3
x-page: 2
x-per-page: 20
x-prev-page: 1
x-total: 172
x-total-pages: 9

Answer 1

您需要将URL括在引号"中，因为问号?被视为通配符，否则，根据您的shell，与号&会将命令发送到后台。 / p>

curl --head --header "PRIVATE-TOKEN: asdfasdf" "https://gitlab.asdfasdf.com/api/v4/projects?page=2"

RESPONSE HEADERS
…
X-Page: 2
…

Gitlab API V4仅利用我发送的参数之一

1 个答案: