Question

在未验证条件状态的情况下，是否可以使用copy Kotlin函数并使用原始对象值属性？或执行此操作的类似功能？

示例：

data class UserEntity(
    id = String,
    email = String,
    firstName = String,
    lastName = String
)

data class UserUpdate(        
    firstName = String?,
    lastName = String?
)

@Service
class UserService(userRepository: UserRepository) {

    fun update(id: String, dto: UserUpdate) = userRepository.save(
        userRepository.findById(id).copy(
            // *it* is not available as the initial object the  
            // copy function is called from.
            firstName = dto.firstName ?: it.firstName,
            // I'd like something like:
            lastName = dto.lastName ?: keepTheOriginalLastNameProperty
        )
    )

}

Answer 1

您可以使用takeIf函数来内联条件。如果谓词为假，它将返回null，这使您可以将其链接到?:中。

firstName = dto.firstName.takeIf { it.isNotEmpty() } ?: user.firstName

它可以与let很好地结合在一起。

val something = other.takeIf { it.someBool }?.let { Something(it) } ?: throw Exception()

编辑：作为对您的编辑的回复，很遗憾，我看到的最佳选择是：

fun update(id: String, dto: UserUpdate) = run {
    userRepository.findById(id).let { user ->
        val firstName = dto.firstName ?: user.firstName
        val lastName = dto.lastName ?: user.lastName
        user.copy(firstName = firstName, lastName = lastName)
    }.let {
        userRepository.save(it)
    }
}

有条件的Kotlin复制功能

1 个答案: