端点查询中的对象循环

Question

我有一个从API搜索端点返回以下内容的函数：

{#1090 ▼
+"took": 3
+"timed_out": false
+"_shards": {#1141 ▶}
+"hits": {#1309 ▼
  +"total": 231
  +"max_score": null
  +"hits": array:10 [▼
    0 => {#1191 ▼
      +"_index": "products"
      +"_type": "product"
      +"_id": "1634"
      +"_score": 5.7772136
      +"_source": {#1214 ▼
        +"category_wrapper_detail": "General 1234:0 - Dark Green 123:25"
        +"wrappers": {#1344 ▼
          +"1": {#1298 ▼
            +"wrapper_code": "123"
            +"id": 525
            +"detail_name": "Dark Green"
            +"detail_code": "25"
          }
        }
        +"template": {#1216 ▼
          +"category": {#1138 ▼
            +"category_code": "1234"
            +"category_name": "General"
            +"category_subcat": 0
            +"id": 135
          }
        }
      }
      +"fields": {#1116 ▶}
    }
    1 => {#1114 ▶}
    2 => {#1083 ▶}
    3 => {#1021 ▶}
    4 => {#950 ▶}
    5 => {#929 ▶}
    6 => {#764 ▶}
    7 => {#770 ▶}
    8 => {#703 ▶}
    9 => {#1535 ▶}
  ]
}

}

结果是正确的，但是我的问题是我不知道该如何正确地进行循环。我通过执行dd($searchResults)得到了上述对象。

您可以看到“命中”有10个数组元素，所以我想说“对于每个“命中”结果，设置“ fieldname” = category_wrapper_detail，然后将每个其他值设置为其自己的变量”

我正在尝试：

foreach($searchResults as $result['hits'] => $result){
  foreach($result['source'] as $source){
      //This is the full concatenated result for a label
      $fullResult = ['category_wrapper_detail'];

      //The following are the individual results that I'll save on the backend eventually
      $categoryName = ['category_name'];
      $categoryCode = ['category_code'];
      $categorySubcat = ['category_subcat'];
      $detailName = ['detailName'];
      $wrapperCode = ['wrapper_code'];
      $detailCode = ['detail_code'];
  }
}

但是它不起作用，我认为这与嵌套循环有关。

如何在这里只返回每个结果所需的值？