Question

我正在根据输入数据进行过滤后尝试更新SQLite数据库。下面是我的代码

public void insert_checkbox(String Str1, String chkboxValue){
        SQLiteDatabase db = this.getWritableDatabase();
        ContentValues contentValues = new ContentValues();
        contentValues.put(COLUMN_CHECKBOX, Str1 );

        db.execSQL("UPDATE " + ResturantEntry.TABLE_NAME + " SET COLUMN_CHECKBOX = '" + Str1 + "' WHERE COLUMN_LOCATION = '" + chkboxValue + "'");
        this.getWritableDatabase().insertOrThrow(ResturantContract.ResturantEntry.TABLE_NAME,"",contentValues);


    }
}

我在SQLiteOpenhelper中创建数据库代码如下

p

ublic void onCreate(SQLiteDatabase db) {
        String SQL_CREATE_RESTURANTS_TABLE = "CREATE TABLE " + ResturantEntry.TABLE_NAME + "("`enter code here`
                + ResturantEntry._ID + " INTEGER PRIMARY KEY AUTOINCREMENT,"
                + ResturantEntry.COLUMN_NAME + " TEXT,"
                + ResturantEntry.COLUMN_TYPE + " TEXT,"
                + ResturantEntry.COLUMN_ADDRESS + " TEXT,"
                + ResturantEntry.COLUMN_LOCATION + " TEXT,"
                + ResturantEntry.COLUMN_GPSCOORDINATES + " INTEGER,"
                + ResturantEntry.COLUMN_TELEPHONE + " INTEGER,"
                + ResturantEntry.COLUMN_OPENINGHOURS + " INTEGER,"
                + ResturantEntry.COLUMN_CLOSINGHOURS + " INTEGER,"
                + ResturantEntry.COLUMN_CHECKBOX + " TEXT,"
                + ResturantEntry.COLUMN_CHECKBOXVALUE + " TEXT);";


        db.execSQL(SQL_CREATE_RESTURANTS_TABLE);


    }

我不断在下面的日志中收到错误

#################################################################
    Error Code : 1 (SQLITE_ERROR)
    Caused By : SQL(query) error or missing database.
        (no such column: COLUMN_CHECKBOX (code 1): , while compiling: UPDATE Resturant SET COLUMN_CHECKBOX = '1' WHERE COLUMN_LOCATION = 'Ajah')
    #################################################################

Answer 1

COLUMN_CHECKBOX是包含列名而不是文字列名的变量名。您不应在SQL中将其放在双引号中。与COLUMN_LOCATION相同。

但是，与其在execSQL()中更正SQL，不如在SQLiteDatabase中使用update() ContentValues方法，会更好。它还可以为您处理诸如SQL注入保护之类的事情。

Answer 2

当您要更新db中的一行时，需要通过该行的主键WHERE进行过滤（通过在ResturantEntry._ID子句中使用），然后执行更新。您似乎没有那个。
您正在混合两种不同的更新方法：ContentValues和直接UPDATE语句。您不需要它们，都选择一个。

Answer 3

请尝试使用SQLiteDatabase更新方法更新代码：-

public int insert_checkbox(String Str1, String chkboxValue)
 { 
  SQLiteDatabase db = this.getWritableDatabase(); 
  ContentValues contentValues = new ContentValues(); 
  contentValues.put(COLUMN_CHECKBOX, Str1 ); 
  String selection = ResturantEntry.COLUMN_LOCATION + " =? ";

  String[] selectionArgs = new String[]{chkboxValue};
 //count denotes the number of rows update 
 int count =   db.update(ResturantEntry.TABLE_NAME,   contentValues,selection  ,selectionArgs ); 
 retun count;
}

希望这会有所帮助。

SQLite更新错误：没有这样的列：COLUMN_CHECKBOX（代码1）：，而编译时：更新

3 个答案: