Question

我有一个表'tbl_content'

运行以下查询时，我可以看到11条记录/数据

SELECT ContentID, CategoryID, Home, Inner
FROM tbl_content
WHERE CategoryID = 1 AND Inner = 2
ORDER BY ContentID DESC

运行以下查询时，我可以看到前4条记录/数据

SELECT ContentID, CategoryID, Home, Inner
FROM tbl_content
WHERE CategoryID = 1 AND Inner = 2
ORDER BY ContentID DESC LIMIT 7, 10

我想更新剩余的前4条记录/数据的值。但不幸的是，它正在产生错误。

UPDATE tbl_content
SET Inner = 1
WHERE CategoryID = 1 AND Inner = 2
ORDER BY ContentID DESC LIMIT 7, 10

任何人都可以提出解决方案吗？

Answer 1

您可以尝试使用IN子句来进行带限制的替换

UPDATE tbl_content SET Inner=1 
WHERE CategoryID=1 AND Inner=2 
AND ContentID  IN ( 
 select contentID from (
  select ContentID  
  from  tbl_content 
  order by ORDER BY ContentID DESC LIMIT 7, 10 ) t

)

或联接

UPDATE tbl_content c 
INNER JOIN (
  select ContentID  
  from  tbl_content 
  order by ORDER BY ContentID DESC LIMIT 7, 10 
) t  on t.ContentID = c.ContentID
SET c.Inner=1 
WHERE c.CategoryID=1 AND c.Inner=2

Answer 2

尝试一下。

UPDATE tbl_content SET Inner=1 WHERE id IN(SELECT ContentId FROM (SELECT ContentID, CategoryID, Home, Inner FROM tbl_content WHERE CategoryID=1 AND Inner=2 ORDER BY ContentID DESC LIMIT 7, 10));

修复MySQL查询语法错误（LIMIT）

2 个答案: