我有2张桌子(person
+ person_products
)
每个人至少有一种产品。
样本人表:
person_id | name
------------------
1 | Alice
2 | Peter
3 | James
person_products表样本:
id | person_id | description | price
------------------------------------
1 | 1 | iphone 5 | 100
2 | 1 | iphone 6 | 200
3 | 1 | samsung | 300
4 | 2 | tv | 110
5 | 3 | oven | 250
6 | 3 | microwave | 260
我要执行以下操作:
SELECT p.person_id,
some_concat_product_descriptions,
some_concat_product_prices
FROM person p
LEFT JOIN person_products p on p.person_id = pp.person_id
预期结果:
person_id | concat_product_descriptions | concat_product_prices
---------------------------------------------------------------
1 | iphone 5, iphone 6, samsung | 100, 200, 300
2 | tv | 110
3 | oven, microwave | 250, 260
我该如何实现?
答案 0 :(得分:1)
<DataTrigger Binding="{Binding Contains}" Value="True">
<Setter Property="Background" Value="Red"/>
</DataTrigger>
答案 1 :(得分:-1)
使用group_concat aggregation function。完全不需要加入。
select
person_id,
group_concat(description) separator ', ' as concat_product_descriptions,
group_concat(price) separator ', ' as concat_product_prices
group by
person_id