java.lang.IllegalArgumentException:无法找到包含以下内容的已配置根目录

时间:2018-08-27 08:08:16

标签: android android-8.0-oreo android-fileprovider

这是我的代码块:

notificationIntent.setDataAndType(FileProvider.getUriForFile(
            context,
            "TrySomething",new File(context.getFilesDir().getAbsolutePath() + "/update_file")
    ),ANDROID_PACKAGE);

这是我的XML文件:

<?xml version="1.0" encoding="utf-8"?>
<paths xmlns:android="http://schemas.android.com/apk/res/android">
    <external-files-path name="myupdater" path="files/update_file"/>
</paths>

但是我得到这个错误:

  

java.lang.IllegalArgumentException:无法找到已配置的根   包含/data/data/com.example.trysomething/files/update_file

我该如何解决?

2 个答案:

答案 0 :(得分:0)

首先在src-> xml文件夹中创建Xml文件,例如 例如名为file_paths_public.xml

<?xml version="1.0" encoding="utf-8"?>
    <paths xmlns:android="http://schemas.android.com/apk/res/android">
        <external-path
            name="external_files"
            path="." />
<root-path
        name="external_files"
        path="/storage/"/>
    </paths>

然后将此代码添加到清单文件中

 <provider
        android:name="android.support.v4.content.FileProvider"
        android:authorities="<your app package>.provider"
        android:exported="false"
        android:grantUriPermissions="true">
        <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/file_paths_public" />
    </provider>

现在创建一个将支持api 26及以下设备的函数 返回有效的uri

 public static Uri getUriFromFile(Context theCtx, File theSrcPath) {
        Uri requirdUri;

        // Above Compile SDKversion: 25 -- Uri.fromFile Not working
        // So we have to use Provider

        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.N) {
            requirdUri = FileProvider.getUriForFile(theCtx,
                    theCtx.getApplicationContext().getPackageName() + ".provider",
                    theSrcPath);
        } else {
            requirdUri = Uri.fromFile(theSrcPath);
        }

        return requirdUri;
    }

现在无论何时需要使用此uri 像

 File FilePath = Environment.getExternalStorageDirectory().toString()/update_file/<here your file name >
   Uri shareImageUri = getUriFromFile(this, <your full file Path Add hear>)

答案 1 :(得分:-1)

  1. 检查清单中是否包含此内容

    <provider
    android:name="android.support.v4.content.FileProvider"
    android:authorities="${applicationId}.provider"
    android:exported="false"
    android:grantUriPermissions="true">
    <meta-data
    android:name="android.support.FILE_PROVIDER_PATHS"
    android:resource="@xml/provider_paths"/>
    </provider>
    
  2. provider_paths:

    <?xml version="1.0" encoding="utf-8"?>
    <paths>
    <external-path name="directory_name" path="."/>
    </paths>
    
  3. 获取文件URI为

    Uri fileUri = FileProvider.getUriForFile(context, getApplicationContext().getPackageName() + ".provider", fileName(FILE))