Question

我有这个json，它返回一些数据并将其放在json数组对象中：

{
"id": "58",
"p": "4297f44b13955235245b2497399d7a",
"name": "0634063306cc06340634063306cc",
"contacts": [{
    "id": "1",
    "name": "test1"
}, {
    "id": "2",
    "name": "test2"
}]
}

我想准备数组，这是我的代码：

联系方式代码：

public class Contact {
@SerializedName("id")
@Expose
private String id;
@SerializedName("name")
@Expose
private String name;

public String getId() {
    return id;
}

public void setId(String id) {
    this.id = id;
}

public Contact withId(String id) {
    this.id = id;
    return this;
}

public String getName() {
    return name;
}

public void setName(String name) {
    this.name = name;
}

public Contact withName(String name) {
    this.name = name;
    return this;
}
   }

这是联系人类代码：

    public class Contacts {
    @SerializedName("id")
@Expose
private String id;
@SerializedName("p")
@Expose
private String p;
@SerializedName("name")
@Expose
private String name;
@SerializedName("contacts")
@Expose
private List<Contact> contacts = null;

public String getId() {
return id;
}

public void setId(String id) {
this.id = id;
}

public Contacts withId(String id) {
this.id = id;
return this;
}

public String getP() {
return p;
}

public void setP(String p) {
this.p = p;
}

public Contacts withP(String p) {
this.p = p;
return this;
}

public String getName() {
return name;
}

public void setName(String name) {
this.name = name;
}

public Contacts withName(String name) {
this.name = name;
return this;
}

public List<Contact> getContacts() {
return contacts;
}

public void setContacts(List<Contact> contacts) {
this.contacts = contacts;
}

public Contacts withContacts(List<Contact> contacts) {
this.contacts = contacts;
return this;
}
    }

我已经写了这个接口来解析数据：

public interface UserLogin {
@GET("/getLogin3.php")
Call<Contacts>getItems();
}

这些是我的活动课中的代码：

Call<Contacts>rows=connection.getItems();
    rows.enqueue(new Callback<Contacts>() {
        @Override
        public void onResponse(Call<Contacts> call, Response<Contacts> response) {
                Log.v("this", "id" + response.body().getId());
                Log.v("this", "name" + response.body().getName());

            Contacts simpleItem = response.body();
            List<Contact>contacts=simpleItem.getContacts();
            for (int i=0; i<contacts.size();i++){
                Log.v("this","result "+ contacts.get(i).getId()+ " - "
                + contacts.get(i).getName());
            }
        }

        @Override
        public void onFailure(Call<Contacts> call, Throwable t) {
            Log.v("this",t.getMessage());
        }
    });

它进入失败方法，错误是：

Expected name at line 2 column 1 path $.

此代码有什么问题？我找不到

Answer 1

尝试一下

Call<Contacts>rows=connection.getItems();
rows.enqueue(new Callback<Contacts>() {
    @Override
    public void onResponse(Call<Contacts> call, Response<Contacts> response) {
           if (response.isSuccessful())
           if (response.body() != null)

        // Contacts simpleItem = response.body();
        List<Contact>contacts=response.body().getContacts() 
        for (int i=0; i<contacts.size();i++){
            Log.v("this","result "+ contacts.get(i).getId()+ " - "
            + contacts.get(i).getName());
        }
    }

    @Override
    public void onFailure(Call<Contacts> call, Throwable t) {
        Log.v("this",t.getMessage());
    }
});

Answer 2

我认为您获取的数据存在问题，您可以通过添加带有Retroift的拦截器来进行检查：

builder是OkHttpClient.Builder的对象，您可能已在代码中使用过。

 builder.interceptors().add(new Interceptor() {
            @Override
            public okhttp3.Response intercept(Chain chain) throws IOException {
                Request request = chain.request();

                request = request.newBuilder()
                        .url(request.url())
                        .build();

                okhttp3.Response response = chain.proceed(request);
// Check the responce here 
Log.i("Response ",response+"");
                return response;
            }
        });

放入有问题的答案。

android-改造2-无法读取json数组并对其进行解析

2 个答案: