我是新来的,所以请考虑。
我已经创建了一个新的画布并在画布中创建了一个矩形,当我为画布设置背景时,我遇到了一个可怕的问题,即背景位于形状上
代码如下:
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
var BB = canvas.getBoundingClientRect();
var offsetX = BB.left;
var offsetY = BB.top;
var WIDTH = canvas.width;
var HEIGHT = canvas.height;
var background = new Image();
background.src = "url_to_image";
// Make sure the image is loaded first otherwise nothing will draw.
background.onload = function(){
ctx.drawImage(background,0,0);
}
<canvas id="canvas" width=450 height=700></canvas>
谢谢
编辑: 我在代码中发现fillStyle函数可以更改背景, 所以我删除了它,取而代之的是:
var w = canvas.width;
var h = canvas.height
var img = new Image();
img.src = "http://www.girija.info/wp-content/uploads/2015/08/Paznja-Sabranost-450x700.png";
img.onload = function () {
var pattern = ctx.createPattern(img, "repeat");
ctx.fillStyle = pattern;
ctx.fillRect(0, 0, w, h);
};
//ctx.fillStyle = "#FAF7F8";
rect(0, 0, WIDTH, HEIGHT);
// redraw each rect in the rects[] array
for (var i = 0; i < rects.length; i++) {
var r = rects[i];
ctx.fillStyle = 'red';
rect(r.x, r.y, r.width, r.height);
}
但是矩形的每次拖动(矩形从堆栈加载并且可以拖动)矩形的背景颜色都会改变
答案 0 :(得分:1)
您可以使用css属性设置背景
var canvas = document.getElementById("canvas");
var ctx = canvas.getContext("2d");
var BB = canvas.getBoundingClientRect();
var offsetX = BB.left;
var offsetY = BB.top;
var WIDTH = canvas.width;
var HEIGHT = canvas.height;
ctx.rect(10, 10, 100, 100);
ctx.fill();
canvas.style.backgroundImage = 'url(https://picsum.photos/450/700)';
<canvas id="canvas" width=450 height=700></canvas>
答案 1 :(得分:0)
var canvas = document.getElementById('canvas'),
context = canvas.getContext('2d');
background_image();
function background_image()
{
background_image = new Image();
background_image.src = 'https://image.ibb.co/kmV8kz/photodune_2359510_smiles_l_22.png';
background_image.onload = function(){
context.drawImage(background_image, 0, 0);
}
}
<canvas id="canvas" width=450 height=700></canvas>