我有六个桌子
online_transaction
| date | id | supplier_id | product code |
online_transaction_enc
| date | id | item |
offline_transaction
| date | id |
offline_transaction_enc
| date | id | item |
产品
| type | product_code |
供应商
| supplier_id | country |
选择日期(在“ 2018年6月1日”和“ 2018年7月30日”之间)且类型=“住户”且国家/地区=“马来西亚”
这些大概是我想要实现的。我想在日期和ID上在线和离线合并项目,因此我将所有项目组合在一起,然后再执行其他要求。 如何在MySQL中做到这一点?
答案 0 :(得分:1)
尝试一下:
select count(a.item) from
(select date, id, item from online_transaction_enc
union
select date, id, item from offline_transaction_enc)a
inner join
(
select date,id,supplier_id,productcode from online_transaction
union
select date,id,supplier_id,productcode from offline_transaction)b
on a.date=b.date and a.id=b.id
inner join supplier on b.supplier_id=supplier.supplier_id
inner join products on b.productcode=products.product_code
where a.date between '20180601' And '20180730' AND Type='household' AND country='Malaysia'
答案 1 :(得分:-1)
SELECT count(item)
FROM online_transaction_enc
INNER JOIN online_transaction_enc ON supplier_id
INNER JOIN products ON supplier_id
...
WHERE WHERE (date BETWEEN '2010-01-30 14:15:55' AND '2010-09-29 10:15:55')
;
此解决方案使用内部联接。我相信这就是您要寻找的。这是更多文档 http://www.mysqltutorial.org/mysql-inner-join.aspx