我的Ajax / HttpServlet错误

时间:2018-08-26 16:11:56

标签: javascript jquery ajax servlets genson

我正在尝试创建一个伪登录页面,该页面将在登录或签入后将我们链接到主页,我使用的是Ajax和servlet,因为这是他们要求在学校使用的。

问题是,当我单击“登录”时,它在我的Ajax中输入了错误,我到处都是,但找不到错误。

这是我的Javascript代码;

$(function() {


$('#connect').on('click',function() {
        var json = formToJSON($('.form'));
        $.ajax({
            url: "/conn",
            type: "POST",
            data:{form:JSON.stringify(json)},
            success: function(response, textStatus, jqXHR) {
                location.href = "http://localhost:8080/home.html";
            },
            error: function(e) {
                console.log(e.message);
            }
        });
    });

    $('#login').on('click',function() {
        var json = formToJSON($('.form'));
        $.ajax({
            url: "/inscr",
            type: "POST",
            data: {form:JSON.stringify(json)},
            success: function(response, textStatus, jqXHR) {
                location.href = "http://localhost:8080/home.html";
            },
            error: function(e) {
                console.log(e.message);
            }
        });
    });
});

var formToJSON = function(form) {
    var data = {};

    data["username"] = $("#username").val();
    data["password"] = $("#password").val();

    console.log(data);
    return data;
}

这是我的Java servlet(我们使用Jetty): MAIN.java;

    import javax.servlet.http.HttpServlet;

import org.eclipse.jetty.server.Server;
import org.eclipse.jetty.servlet.DefaultServlet;
import org.eclipse.jetty.servlet.ServletHolder;
import org.eclipse.jetty.webapp.WebAppContext;

public class Main {
    public static void main(String[] args)throws Exception{
        Server server = new Server(8080);
        WebAppContext context = new WebAppContext();
        context.setResourceBase("www");
        context.setContextPath("/");

        HttpServlet ds=new DefaultServlet();
        HttpServlet c=new Connection();
        HttpServlet i=new Inscrir();

        context.addServlet(new ServletHolder(i), "/inscr");
        context.addServlet(new ServletHolder(c), "/conn");
        context.addServlet(new ServletHolder(ds), "/");

        server.setHandler(context);

        server.start();
    }
}

Inscrir.java;

import java.io.IOException;
import java.security.InvalidKeyException;
import java.security.NoSuchAlgorithmException;
import java.security.SignatureException;
import java.text.SimpleDateFormat;
import java.util.HashMap;
import java.util.Map;

import javax.servlet.ServletException;
import javax.servlet.http.Cookie;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

import com.auth0.jwt.JWTSigner;
import com.auth0.jwt.JWTVerifier;
import com.auth0.jwt.JWTVerifyException;
import com.owlike.genson.Genson;
import com.owlike.genson.GensonBuilder;

public class Inscrir extends HttpServlet {

    private static String SECRET = "jkdh lqjk lcx wuich liuhza";
    Genson genson = new GensonBuilder().create();

    @Override
    protected void doPost(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
        try {
            System.out.println("ok");
            Map<String, Object> claims = new HashMap<String, Object>();
            String json = req.getParameter("form");
            User user = genson.deserialize(json, User.class);

            claims.put(user.getName(), user);

            String token = new JWTSigner(SECRET).sign(claims);

            System.out.println("Chaîne JWT=" + token);

            /* cette chaîne peut être mise en cookie par exemple : */

            Cookie cookie = new Cookie("user", token);
            cookie.setPath("/");
            cookie.setMaxAge(60 * 60 * 24);
            resp.addCookie(cookie);

            Map<String, Object> decodedPayload = new JWTVerifier(SECRET).verify(token);
            System.out.println("Contenu=" + decodedPayload);
        } catch (SignatureException signatureException) {
            System.err.println("Invalid signature!");
        } catch (IllegalStateException illegalStateException) {
            System.err.println("Invalid Token! " + illegalStateException);
        } catch (InvalidKeyException e) {
            System.err.println("Invalid Key! " + e);
        } catch (NoSuchAlgorithmException e) {
            System.err.println("Invalid Algorithm! " + e);
        } catch (IOException e) {
            e.printStackTrace();
        } catch (JWTVerifyException e) {
            System.err.println("JWT Verify Exception! " + e);
        }
    }

}

User.java;

public class User {
    private String name;
    private String psw;

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public String getPsw() {
        return psw;
    }

    public void setPsw(String psw) {
        this.psw = psw;
    }

    public User(String name, String psw) {
        super();
        this.name = name;
        this.psw = psw;
    }
}

当我单击“登录”时,控制台中也会出现未定义的内容。

0 个答案:

没有答案