Question

对于下面给出的以下示例，我需要一个代码。这是我尝试的代码，矩阵末尾不应包含换行符（\ n）：

r=int(input())
c=int(input())
count=1

for i in range(r):
    for j in range(c):
        print(count)
        count=count+1
print()

输入

r=2

c=2

输出

 1 2

 3 4

Answer 1

from __future__ import print_function
m = int(input("Enter the row:"))
n = int(input("Enter the column:"))

num = 1
# iterate over the rows and print each row
for i in range(m):
    row = " ".join(map(str, range(i*n + 1, (i+1)*n + 1)))
    print(row)

由于对问题进行了编辑：

m = int(input("Enter the row:"))
n = int(input("Enter the column:"))

count = 1
for i in range(m):
    for j in range(n):
        print(count, end=" ")
        count += 1
    print()

Answer 2

r = int(input())
c = int(input())
count = 1
for i in range(r):
      for j in range(c): 
            print(count,end=' ')
            count=count+1
      print()

Answer 3

关闭代码：

def print_matrix(rows, columns):
    # maximum width of column, including spaces
    pad_len = len(str(rows * columns)) + 1

    for y in range(rows):
        for x in range(columns):
            print("{n:>{pad}}".format(
                n=y * columns + x + 1,
                pad=pad_len
            ), end='')
        print()

print_matrix(18, 37)

我已将计数器替换为根据x和y计算得出的值；希望您能看到如何完成。而且，它使用填充，以便即使是很大的数字，列也始终对齐。

用Python打印矩阵形式

3 个答案: