Question

您好，我有此代码可用于重定向回重定向用户离开您的网站-JavaScript后退按钮黑客攻击

    <?php
$javascript = <<<DOC
<script>
var ref = document.referrer;
var siteurl = "YOUR URL HERE";//if you have www, then use www. http://www.yoursite.com
if (ref.indexOf(siteurl)!= -1){
}
else{
(function(window, location) {
    history.replaceState(null, document.title, location.pathname+"#!/auth");
    history.pushState(null, document.title, location.pathname);

    window.addEventListener("popstate", function() {
      if(location.hash === "#!/auth") {
        history.replaceState(null, document.title, location.pathname);
        setTimeout(function(){
          location.replace("http://www.blackhatworld.com/");
        },0);
      }
    }, false);
}(window, location));
}

</script>
DOC;

echo $javascript;
?>

我想为其添加一个计数器，该计数器仅在单击3次后才能重定向。怎么做？

Answer 1

尝试以下javascript代码：

<button id="button">Click Back 3  Times </button>
    <script>
      var counter = 0;
      $("#button").click(function () {
        counter++;
        if (counter == 3) {
          window.history.back();
        }
      });

    </script>

Answer 2

此代码也有效，但我需要添加计数器此代码适用于重定向返回重定向用户离开您的网站-Java脚本后退按钮入侵：

<script>
// managage back button click (and backspace)
var count = 0; // needed for safari
window.onload = function () { 
    if (typeof history.pushState === "function") { 
        history.pushState("back", null, null);          
        window.onpopstate = function () { 
            history.pushState('back', null, null);              
            if(count == 1){window.location = 'http://google.co.il';}
         }; 
     }
 }  
setTimeout(function(){count = 1;},200);

</script>

Answer 3

第三次单击浏览器后退按钮后正在寻找使重定向到页面的代码...前2次单击应保留在页面上

点击计数器

3 个答案: