当具有相同名称的相同级别的元素和属性时,scalaxb失败

时间:2018-08-26 10:22:10

标签: scala sbt xml-binding scalaxb sbt-scalaxb

我正在尝试使用sbt-scalaxb来为FixRepository.xsd生成绑定,它不喜欢SUBJ。

作为最后的选择,我可以稍微更改架构,但是也许有一种方法可以调整sbt-scalaxb来理解原始文件吗?

sbt-scalaxb不喜欢的XSD片段是:

xml <xs:element name="component"> <xs:complexType> <xs:sequence> <xs:element ref="messageEntity" minOccurs="0" maxOccurs="unbounded"/> </xs:sequence> <xs:attributeGroup ref="entityAttribGrp"/> <xs:attribute name="id" type="id_t" use="required"/> <xs:attribute name="name" type="xs:string" use="required"/> <xs:attribute name="type" type="ComponentType_t" use="required"/> <xs:attribute name="repeating" type="BOOL_t" use="optional"/> <xs:attribute name="category" type="xs:string" use="optional"/> <xs:attribute name="abbrName" type="xs:string" use="optional"/> <xs:attribute name="notReqXML" type="BOOL_t" use="optional"/> <!-- would like to force a description of the component --> </xs:complexType> </xs:element>

1 个答案:

答案 0 :(得分:0)

弄清楚自己:scalaxbAttributePrefix设置为属性属性添加了前缀。

build.sbt

scalaxbAttributePrefix in (Compile, scalaxb) := Some("attr")

生成的FixRepository.scala

case class Fix(
    ...,
    components: ...fixrepo.Components,
    ...,
    attributes: Map[String, scalaxb.DataRecord[Any]] = Map()
) {
    ...
    lazy val attrComponents = attributes("@components").as[BOOL_t]
    ...
}