多处理Python-如何执行共享类实例

时间:2018-08-26 07:14:31

标签: python-3.x multiprocessing spyder

我没有为我的查询提到搜索结果,也找不到我的解决方案。 下面的代码用于模拟几乎与我的需求相等的代码。我正在使用spyder IDE,在某些情况下,我将在spyder的Ipython控制台中调用该函数并更改变量..etc。在使用线程处理时,会发现一些性能延迟,以及如何在多处理中实现这一点,因为我还必须在实例和函数之间共享数据。

readonly

使用线程共享内存..以及如何在多处理中使用?

import time
import struct
import queue
import random
from threading import Thread

# Class for Data generation and processing

class datagenerator:
    def __init__(self):
        self.st = struct.Struct("<lh20s200s100s")
        self.notbreakloop = True
        self.que = queue.Queue()
        self.dict = {}
        self.dictcal = {}

    def bytesgenerator(self):
        while self.notbreakloop:
            i = random.randint(10,10000)
            bytesstruct = self.st.pack(1,i,"20s".encode("ascii"),"200s".encode("ascii"), "100s".encode("ascii"))
            self.que.put(bytesstruct)
            time.sleep(5)

    def worker(self):
        while self.notbreakloop:
            try:
                bytesmsg = self.que.get()
                tup = self.st.unpack(bytesmsg)
                self.dict[tup[0]] = tup
                time.sleep(4)
            except Exception:
                pass

    def calculator(self,key,a,b,):
        self.dictcal[key] = a/b

# User class

class strategy:
    def __init__(self, val):
        self.val = val
    def userrun(self):
        while tt.notbreakloop:
            try:
                #getting value from datagenerated instance
                val1 = tt.dict.get(1,())[1]
                tt.calculator(key=str(self.val), a=val1, b=self.val)
                time.sleep(3)
            except IndexError:
                pass
            except Exception:
                pass


tt = datagenerator()
s1 = strategy(5)
s2 = strategy(10)
s3 = strategy(15)

在Ipython控制台中调用dict值,有时我也可以更改变量状态

data = Thread(target=tt.bytesgenerator)
data2 = Thread(target=tt.worker)
user1 = Thread(target=s1.userrun)
user2 = Thread(target=s2.userrun)
user3 = Thread(target=s3.userrun)

data.start()
data2.start()
user1.start()
user2.start()
user3.start()

0 个答案:

没有答案
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