在没有GROUP BY的聚合查询中，SELECT列表的表达式＃2包含非聚合列'a.b.id'；

Question

请帮助我解决此问题。 我的代码：

$dn1 = mysqli_fetch_array(mysqli_query($con, '
select count(id) as recip
     , id as recipid
     , (select count(*) from pm) as npm 
  from users 
 where username="'.$recip.'"'
 ));

它给出以下错误

  

错误：在没有GROUP BY的聚合查询中，SELECT的表达式＃2   列表包含未聚合的列'omapm.users.id';这是   与sql_mode = only_full_group_by

不兼容

请帮助我更正此问题。 谢谢！

Answer 1

$dn1 = mysqli_fetch_array(mysqli_query($con, 
    'select count(id) as recip, id as recipid, 
        (select count(*) from pm) as npm 
    from users 
    where username="'.$recip.'"
    group by recipid, npm'));

无论如何，您不应该在sql命令中使用php var ..这样，您就有可能遭受sqlinjection ..您应该为准备好的语句和绑定参数而为自己的mysql驱动程序che一下。