我找不到一种方法来获取未在特定日期创建的记录。日期为iso格式,但我只需要比较日期部分(不包括时间)。
like where rec_date != '2018-08-02'
我已经很难获取特定日期的记录,但是我可以使用以下方法进行管理
var param_date = '2018-08-23T09:47:00Z'
var day = moment(param_date, "YYYY-MM-DD")
var pday = moment(param_date, "YYYY-MM-DD").subtract(1, 'day')
var nday = moment(param_date, "YYYY-MM-DD").add(1, 'day')
Model.find({
$and: [
// match exact date
{"rec_date": {$gt: day}},
{"rec_date": {$lt: day2}}
]
},
function(err,docs) {
res.json(docs)
} );
但是我不知道该怎么做
$ ne似乎不起作用,因为它正在比较整个ISO日期,只需要比较日期部分即可。
答案 0 :(得分:1)
找到确切日期时,您可以执行与当前操作相反的操作:
#include <SFML/Graphics.hpp>
#include <iostream>
int main(){
sf::RenderWindow window(sf::VideoMode(800, 600), "This is the title");
window.setFramerateLimit(60);
sf::RectangleShape rect(sf::Vector2f(20, 20));
rect.setFillColor(sf::Color::Green);
rect.setPosition(sf::Vector2f(50, 50));
// Timing
sf::Clock clock;
while (window.isOpen()){
// Update the delta time to measure movement accurately
sf::Time dt = clock.restart();
// Convert to seconds to do the maths
float dtAsSeconds = dt.asSeconds();
// For debuging, print the time to the terminal
// It illustrates the differences
std::cout << "Time step: " << dtAsSeconds << '\n';
// Calculate movement per dt
// Since the dt is a very small number,
// you have to multiply it with a large number to see faster movement
float movement = 250.0f * dtAsSeconds;
if (sf::Keyboard::isKeyPressed(sf::Keyboard::Up)){
rect.move(0, -movement);
}
if (sf::Keyboard::isKeyPressed(sf::Keyboard::Down)){
rect.move(0, movement);
}
if (sf::Keyboard::isKeyPressed(sf::Keyboard::Left)){
rect.move(-movement, 0);
}
if (sf::Keyboard::isKeyPressed(sf::Keyboard::Right)){
rect.move(movement, 0);
}
sf::Event event;
while (window.pollEvent(event)){
if (event.type == sf::Event::Closed){
window.close();
}
}
window.clear();
window.draw(rect);
window.display();
}
return 0;
}