我在shell脚本中有一个字符串
list="apr/2018-06-24 17_10_39/2018-06-24 17_10_39.html
apr/2018-06-24 17_10_39/access_log.zip
apr/2018-06-25 17_12_48/2018-06-25 17_12_48.html
apr/2018-06-25 17_12_48/access_log.zip
apr/2018-06-26 17_13_36/2018-06-26 17_13_36.html
DS_BLS_731.dat
DS_BLS_732.dat
DS_BLS_733.dat
apr/2018-06-26 17_13_37/ DS_BLS_739.dat
apr/2018-06-26 17_13_38/ DS_BLS_738.dat
apr/2018-06-26 17_13_39/ DS_BLS_737.dat"
我需要找到DS_BLS_max(序列号).dat
此处DS_BLS_max(序列号).dat = DS_BLS_739.dat
答案 0 :(得分:0)
grep -o 'DS_BLS_[0-9]*\.dat' <<< "$list" | sort -V | tail -n 1
输出:
DS_BLS_739.dat