Question

CREATE TABLE test
(
    [message] NVARCHAR(100) NULL,
)
INSERT INTO test
    values
   ('Location set to: Loc1, Order: 1, item: shirt-red.large, company: 01, store: 01'),
   ('Location set to: Loc1, Order: 1, item: shirt-red.medium, company: 01, store: 01'), 
   ('Location set to: Loc2, Order: 220, item: shirt-blue.small, company: 01, store: 089'),
   ('Location set to: Loc2, Order: 220, item: shirt-blue.medium, company: 01, store: 089')

在SQL Server（2016）中，我尝试使用'shirt-red.large'来搜索以上列中的完整项目字符串（例如'shirt-blue.small'，CHARINDEX等） {1}}和'Item: '，但出现以下错误

“传递给LEFT或SUBSTRING函数的无效长度参数”

这与', '在字符串中多次出现有关吗？结果是隔离项目的最佳方法是什么？

Answer 1

自2016年起，您可以通过string_split()

示例或dbFiddle

Select Item = ltrim(rtrim(replace(b.value,'item:','')))
 From  Test A
 Cross Apply string_split([message],',') b
 where charindex('item:',value)>0

返回

Item
shirt-red.large
shirt-red.medium
shirt-blue.small
shirt-blue.medium

注意：如果要查看NULL，请使用Outer Apply

Answer 2

不确定您的代码是什么，但这应该可以工作

replace(substring([message],charindex('item: ',[message]),len([message]) - charindex(', company',[message])),',','')

或者没有项目

left(substring([message],charindex('item: ',[message]) + 6,99),charindex(',',substring([message],charindex('item: ',[message]) + 6,99)) - 1)

这里正在起作用：

declare @test TABLE ( [message] NVARCHAR(100) NULL)

INSERT INTO @test
values
('Location set to: Loc1, Order: 1, item: shirt-red.large, company: 01, store: 01'),
('Location set to: Loc1, Order: 1, item: shirt-red.medium, company: 01, store: 01'), 
('Location set to: Loc2, Order: 220, item: shirt-blue.small, company: 01, store: 089'),
('Location set to: Loc2, Order: 220, item: shirt-blue.medium, company: 01, store: 089')

select 
    withItem = replace(substring([message],charindex('item: ',[message]),len([message]) - charindex(', company',[message])),',','')
    ,withoutItem = left(substring([message],charindex('item: ',[message]) + 6,99),charindex(',',substring([message],charindex('item: ',[message]) + 6,99)) - 1)
from @test

Answer 3

这是一个解决方案：

SELECT SUBSTRING([message],
    CHARINDEX('item: ', [message])+6,
    CHARINDEX(',',message,CHARINDEX('item: ', [message]))-CHARINDEX('item: ', [message])-6)
FROM test

SQL Server-特定文本之间的列的子字符串部分

3 个答案: