Question

ArrayList自定义类

ArrayList<ItemClass> nomenclatureList

有一个onItemClickListener

   listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {

    @Override
    public void onItemClick(AdapterView<?> adapterView, View view, int position, long id) {
        ItemClass word = nomenclatureList.get(position);
        int singleImg = word.getImageResourse();
        String singleName = word.getNomenclatureName();
        String singleWeight = word.getNomenclatureWeight();
        String singleBrand = word.getNomeclatureBrand();
        String singleBar = word.getNomenclatureBarCode();
        String singlePercent = word.getNomenclaturePercent();
        String singleComposition = word.getNomenclatureComposition();
        String singlePack = word.getNomenclaturePack();
        Intent intent = new Intent(ItemListGKI.this, ItemSingle.class);
        intent.putExtra("SINGLE_IMG_KEY", singleImg);
        intent.putExtra("SINGLE_NAME_KEY", singleName);
        intent.putExtra("SINGLE_WEIGHT_KEY", singleWeight);
        intent.putExtra("SINGLE_BRAND_KEY", singleBrand);
        intent.putExtra("SINGLE_BAR_KEY", singleBar);
        intent.putExtra("SINGLE_PERCENT_KEY", singlePercent);
        intent.putExtra("SINGLE_COMPOSITION_KEY", singleComposition);
        intent.putExtra("SINGLE_PACK_KEY", singlePack);
        startActivity(intent);
    }
});

并且有用于从此ArrayList搜索的代码

    @Override
        public boolean onQueryTextChange(String newText) {
            boolean success = false;
            ArrayList<String> tempList = new ArrayList<>();
            for(ItemClass temp : nomenclatureList){
                if(temp.getNomenclatureName().toLowerCase().contains(newText.toLowerCase())){
                    tempList.add(temp.getNomenclatureName());
                    ArrayAdapter<String> adapter = new ArrayAdapter<>(ItemListGKI.this, android.R.layout.simple_list_item_1, tempList);
                    listView.setAdapter(adapter);
                    tempList.size();
                    success = true;
                }
            }
        return success;
    }

当我单击搜索结果项时，打开的活动信息错误。如果我不使用搜索就单击项目-一切都OK。

我不知道该怎么做。

Answer 1

根据此处定义的API-> https://developer.android.com/reference/android/widget/AdapterView.OnItemClickListener

onItemClick(AdapterView<?> adapterView, View view, int position, long id)

您的代码正在考虑position来检索被单击的项目。我相信应该是身份证。尝试更换

ItemClass word = nomenclatureList.get(position);

使用

ItemClass word = nomenclatureList.get(id);

Answer 2

替换此：

ItemClass word = nomenclatureList.get(position);

与此

ItemClass word = (ItemClass) adapterView.getItemAtPosition(position);

为什么？因为当您搜索或过滤数据时nomenclatureList的数据与设置的适配器不同，因此例如nomenclatureList.get(5)与(ItemClass) adapterView.getItemAtPosition(position);

不同

现在应在onQueryTextChange中输入：

 @Override
        public boolean onQueryTextChange(String newText) {
            boolean success = false;
            ArrayList<ItemClass> tempList = new ArrayList<>();
            for(ItemClass temp : nomenclatureList){
                if(temp.getNomenclatureName().toLowerCase().contains(newText.toLowerCase())){
                    tempList.add(temp);
                }
            }
             ArrayAdapter<String> adapter = new ArrayAdapter<>(ItemListGKI.this, android.R.layout.simple_list_item_1, tempList);
             listView.setAdapter(adapter);
             tempList.size();
             if(tempList.size() > 0){
                success = true;
            }
        return success;
    }

单击搜索结果项时结果页无效

2 个答案: