Question

我在python中有以下代码：

features = {}
    for string in vector:
        string = 'name1:value1 name2:value2 name3:value3'
        name,value = string.split(":");
        features[self._getFeatureId(name)] = float(value);
    return features

但是当我运行代码时，它会出现以下错误：

name,value = string.split(":");
ValueError: too many values to unpack

这是一个for循环，它假定将它们分成3对不同的名称和值。代码有什么问题？

Answer 1

string = "name1:value1 name2:value2 name3:value3"
split_on_colon = string.split(":");  # output = ['name1', 'value1 name2', 'value2 name3', 'value3']
split_on_space = string.split(); # No argument means split on white space; output = ['name1:value1', 'name2:value2', 'name3:value3']
# The split you desire is on space and THEN split each item on colon
desired_split = [s.split(':') for s in string.split()] # output = [['name1', 'value1'], ['name2', 'value2'], ['name3', 'value3']]

此外，错误ValueError: too many values to unpack也无法清除。从字面上说，您正在尝试解压缩比迭代器中小的值。

Answer 2

我还设法使它与以下代码一起使用，方法是先用“”分割，然后对每个名称值对，用“：”分割。

features = {}
    for string in vector:
        string = name1:value1 name2:value2 name3:value3
        valueTemp = string.split(" ");
        for string2 in valueTemp:
            name,value = string2.split(":");
            features[self._getFeatureId(name)] = float(value);
    return features

Python在for循环中拆分为多对（名称：值）输出

2 个答案: