Question

我有以下内容，

CREATE TABLE t (
  id          int,
  events      text, -- may be 'HR1', 'HR2', 'HR3', etc Or 'BP'
  event_value int
);

events可以是HR1 / HR2（id具有HR1或HR2，但不能同时具有两者）或任何其他事件：例如`BP）
每个id都有几行。

我基本上想选择HR1或HR2（取决于该ID使用哪个ID）的所有ID都在50到110之间的ID。

如果所有组的值都在50到110之间，则对HR1或HR2的查询将返回不同的id和event。

下表是一个示例：

ID         |  event  | event value
-----------+---------+-------------
     1        'HR1'       80
     1        'HR1'       90
     1        'HR1'       72
     1        'HR1'       91
     1        'HR1'       69
     1        'BP'        2.3
-
     2        'HR1'       90
     2        'HR1'       40
     2        'HR1'       39
-
     3        'HR2'       200
     3        'HR2'       230
     3        'HR2'       85
-
     4        'HR2'       90
     4        'HR2'       80
     4        'HR2'       90

我想要以下输出：

subject_id  | event
------------+--------
     1        'HR1'
     4        'HR2'

Answer 1

我会用NOT EXISTS和DISTINCT subject_id,event来制作。

SELECT DISTINCT id,event  
FROM t AS t1
WHERE NOT EXISTS(
    SELECT 1 
    FROM t AS t2
    WHERE (t2.event_value < 50 OR t2.event_value > 110)
        AND t1.id = t2.id
        AND t1.event = t2.event
)
AND t1.event in ('HR1','HR2');

Answer 2

索尔斯滕的答案很好，但我将其表达为：

select subject_id,
       min(event) -- only one event per subject
from mytable
where event in ('HR1', 'HR2')
group by subject_id
having min(event_value) >= 50 and
       max(event_value) <= 110
order by subject_id;

Answer 3

此答案不再有效，因为OP更改了要求。

<罢工> 不，这并不复杂。您要排除存在HR1 / 2记录且值超出给定范围的主题。因此，请使用NOT EXISTS或NOT IN。

~~select * from mytable where subject_id not in ( select subject_id from mytable where event in ('HR1', 'HR2') and event_value not between 50 and 100 ) order by subject_id;~~

Answer 4

您已经更改了所需的输出，这使此请求完全不同。您现在想要每个主题一行，一个汇总：

SELECT id, event
FROM t
WHERE event in ('HR1', 'HR2')
GROUP BY id, event
HAVING count(CASE WHEN event_value NOT BETWEEN 50 AND 110 THEN 1 END) = 0
ORDER BY id;

仅选择某些列仅包含特定值的ID

4 个答案: