Question

我试图通过将句子分为单个单词来使单词反击。我尝试通过使用split方法（针对对象String）来实现此目的。但是，由于循环在中途终止，因此我难以计算单词数。你能帮我吗？

所需：找出一个单词在一个单词中重复多少次。

public static void main(String[] args) {
    int count = 0, i=0;
    int max,a;
    ArrayList<Integer> lastCount = new ArrayList<Integer>();
    String yazi ="How ı can do that? I don't know. Can you help me? I need help for counter. Thanks in advance for all.";
    String yazi1 = yazi.replace(",","");
    yazi1 = yazi1.replace(".", "");
    yazi1 = yazi1.replace("?", "");
    yazi1 = yazi1.replace("!", "");
    yazi1 = yazi1.toLowerCase();
    yazi1 = yazi1.replace("ı", "i");
    String[] words = yazi1.split(" ");
    for(a=0; a < words.length; a++) {
        while(i<words.length){
            if(words[a].equals(words[i])) {
                max = 0;
                lastCount.add(a, max+1);
            }
            i++;
        } 
        System.out.println(a+1 +". Word: " + words[a] + " || Counter: "+lastCount.get(a));
    }
}

Answer 1

首先，您应该初始化a和i；它消除了混乱并使其更易于阅读。第二，您应该使用嵌套的for循环，而不是for循环和while循环。第三，我相信一旦words.length到达a，您就不会重置回到0。i为0时，words.length到a，迭代1完成。 i转到1，但是words.length仍然是a，因此什么也没发生。重复执行直到words.length变为a，程序停止。几乎什么都没有完成。我相信可以通过使i和public static void main(String[] args) { int count = 0; int max = 0; ArrayList<Integer> lastCount = new ArrayList<Integer>(); String yazi ="How ı can do that? I don't know. Can you help me? I need help for counter. Thanks in advance for all."; String yazi1 = yazi.replace(",",""); yazi1 = yazi1.replace(".", ""); yazi1 = yazi1.replace("?", ""); yazi1 = yazi1.replace("!", ""); yazi1 = yazi1.toLowerCase(); yazi1 = yazi1.replace("ı", "i"); String[] words = yazi1.split(" "); for(int a=0; a < words.length; a++) { for(int i=0; i < words.length; i++){ if(words[a].equals(words[i])) { max = 0; lastCount.add(a, max+1); } } System.out.println(a+1 +". Word: " + words[a] + " || Counter: "+lastCount.get(a)); }这两个仅在for循环中存在的局部变量来解决此问题。该代码应变为：

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}

在Java中站立While循环

1 个答案: