Question

如何在特定工作表而不是整个电子表格上运行此脚本？

function deleteQCOrder() {
  var sheet = SpreadsheetApp.getActiveSheet();
  var rows = sheet.getDataRange();
  var numRows = rows.getNumRows();
  var values = rows.getValues();

  var rowsDeleted = 0;
  for (var i = 0; i <= numRows - 1; i++) {
    var row = values[i];
    if (row[4] == 'Delete' || row[4] == '') { // This searches all cells in columns A (change to row[1] for columns B and so on) and deletes row if cell is empty or has value 'delete'.
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }
};

例如，如果我想在“ Sheet1” 上运行它，我会尝试：

function deleteQCOrder() {
  var sheet = SpreadsheetApp.getActiveSheet();

  var ss = sheet.getSheetByName('Sheet1');

  var rows = ss.getDataRange();
  var numRows = rows.getNumRows();
  var values = rows.getValues();

  var rowsDeleted = 0;
  for (var i = 0; i <= numRows - 1; i++) {
    var row = values[i];
    if (row[4] == 'Delete' || row[4] == '') { // This searches all cells in columns A (change to row[1] for columns B and so on) and deletes row if cell is empty or has value 'delete'.
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }
};

但没有运行，却出现此错误：

TypeError：在对象Sheet中找不到函数getSheetByName。（第3行，文件“删除订单号”。）

Answer 1

您在代码中所做的事情是获得一个sheet对象，该对象当前是活动工作表

var sheet = SpreadsheetApp.getActiveSheet();

然后您尝试从工作表对象中获取工作表对象，这是错误的地方

var ss = sheet.getSheetByName('Sheet1');

您需要做的是从电子表格对象中找到一个表格对象，如下所示：

function deleteQCOrder() {
  //correct use of SpreadsheetApp for your case
  var ss = SpreadsheetApp.getActiveSpreadsheet();
  var sheet = ss.getSheetByName('Sheet1');
  var range = sheet.getDataRange();
  var numRows = range.getNumRows();
  var values = range.getValues();
  var rowsDeleted = 0;
  for (var i = 0; i <= numRows - 1; i++) {
    var row = values[i];
    if (row[4] == 'Delete' || row[4] == '') {
      sheet.deleteRow((parseInt(i)+1) - rowsDeleted);
      rowsDeleted++;
    }
  }
};

Answer 2

您必须使用电子表格对象来获取工作表对象。在第二段代码中，您将获取工作表而不是电子表格。

您可以使用以下方法获取电子表格对象：

var ss = SpreadsheetApp.getActiveSpreadsheet();

然后您可以使用getSheetByName获取“ Sheet1”：

var sheet = ss.getSheetByName('Sheet1');

更改脚本以在特定工作表上运行会引发TypeError

2 个答案: