Question

我是PHP编程的新手，我需要您的帮助，如何为从数据库接收的信息创建一个表，或者如何从数据库中检索所有数据？一次，没有为每行信息重写该表？这是我的代码和图片：

<?php
  include_once 'includes/dbh.inc.php';
?>
<!DOCTYPE html>
<html lang="en" dir="ltr">
  <head>
    <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
    <meta charset="utf-8">
    <title>mysql connect</title>
  </head>
  <body>
    <?php
      $sql = "SELECT * FROM users;";
      $results = mysqli_query($conn, $sql);
      $resultCheck = mysqli_num_rows($results);

      if ($resultCheck > 0){
        while ($row = mysqli_fetch_assoc($results)) {


          echo '<center><table class="table table-dark"><thead><tr><th scope="col">#</th><th scope="col">Nume</th></tr></thead><tbody><tr><th scope="row">#</th><td>'.$row['user_last']."</td></tr></tbody></table></center> ";

        }
      }
    ?>

  </body>
  <script src="https://code.jquery.com/jquery-3.3.1.slim.min.js" integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo" crossorigin="anonymous"></script>
  <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.3/umd/popper.min.js" integrity="sha384-ZMP7rVo3mIykV+2+9J3UJ46jBk0WLaUAdn689aCwoqbBJiSnjAK/l8WvCWPIPm49" crossorigin="anonymous"></script>
  <script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js" integrity="sha384-ChfqqxuZUCnJSK3+MXmPNIyE6ZbWh2IMqE241rYiqJxyMiZ6OW/JmZQ5stwEULTy" crossorigin="anonymous"></script>
</html>

Answer 1

您只需要循环tr而不是整个表。像下面一样

<?php
      include_once 'includes/dbh.inc.php';
    ?>
  <!DOCTYPE html>
  <html lang="en" dir="ltr">

  <head>
    <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
    <meta charset="utf-8">
    <title>mysql connect</title>
  </head>

  <body>
    <table class="table table-dark">
      <thead>
        <tr>
          <th scope="col">#</th>
          <th scope="col">Nume</th>
        </tr>
      </thead>
      <tbody>
        <?php
          $sql = "SELECT * FROM users;";
          $results = mysqli_query($conn, $sql);
          $resultCheck = mysqli_num_rows($results);

          if ($resultCheck > 0){
           $i=1;
            while ($row = mysqli_fetch_assoc($results)) {
              echo '<tr><th scope="row">'.$i.'</th><td>'.$row['user_last']."</td></tr>";
              $i++;
            }
          }
        ?>
      </tbody>
    </table>
  </body>
  <script src="https://code.jquery.com/jquery-3.3.1.slim.min.js" integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo" crossorigin="anonymous"></script>
  <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.3/umd/popper.min.js" integrity="sha384-ZMP7rVo3mIykV+2+9J3UJ46jBk0WLaUAdn689aCwoqbBJiSnjAK/l8WvCWPIPm49" crossorigin="anonymous"></script>
  <script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js" integrity="sha384-ChfqqxuZUCnJSK3+MXmPNIyE6ZbWh2IMqE241rYiqJxyMiZ6OW/JmZQ5stwEULTy" crossorigin="anonymous"></script>

  </html>

Answer 2

在您的while循环中尝试一下

<th>#</th>
<th>firstname</th>

<?php 
 Echo "<tr>
               <td>{$row['id']}</td>
                <td>{$row['firstname']}</td>
             </tr>";

?>

如果这不起作用，请尝试在id和firstname的索引后面放置半冒号。希望这会有所帮助

PHP在HTML表中回显

2 个答案: