Question

我想从java发送两个数组到oracle存储过程。第一个数组是字符串数组，第二个是字符数组我该怎么做？

Answer 1

以下是如何操作的示例。

以下脚本在数据库中设置表，类型和存储过程。该过程采用数组类型的参数，并将数组的每一行插入表中：

CREATE TABLE strings (s VARCHAR(4000));

CREATE TYPE t_varchar2_array AS TABLE OF VARCHAR2(4000);
/

CREATE OR REPLACE PROCEDURE p_array_test(
    p_strings      t_varchar2_array
)
AS
BEGIN
  FOR i IN 1..p_strings.COUNT
  LOOP
    INSERT INTO strings (s) VALUES (p_strings(i));
  END LOOP;
END;
/

Java代码然后演示如何将数组传递到此存储过程：

import java.sql.*;
import oracle.jdbc.*;
import oracle.sql.*;

public class ArrayTest {
    public static void main(String[] args) throws Exception {
        DriverManager.registerDriver(new OracleDriver());
        Connection conn = DriverManager.getConnection(
            "jdbc:oracle:thin:@localhost:1521:xe", "user", "pass");

        CallableStatement stmt = conn.prepareCall("BEGIN p_array_test(?); END;");

        // The first parameter here should be the name of the array type.
        // It's been capitalised here since I created it without using
        // double quotes.
        ArrayDescriptor arrDesc =
            ArrayDescriptor.createDescriptor("T_VARCHAR2_ARRAY", conn);

        String[] data = { "one", "two", "three" };
        Array array = new ARRAY(arrDesc, conn, data);
        stmt.setArray(1, array);
        stmt.execute();

        conn.commit();
        conn.close();
    }
}

如果您运行SQL脚本然后运行Java类，然后查询表strings，您应该会发现所有数据都已插入表中。

当你说'一组字符'时，我猜你的意思是一个Java char数组。如果我猜对了，那么我认为你最好将char转换为String s然后使用与上述相同的方法。

Answer 2

看这里： http://download.oracle.com/docs/cd/B19306_01/java.102/b14355/oraarr.htm#i1058512

这是我的简短例子：

1）在数据库

上

SQL> create or replace type string_array as table of varchar2(100);
  2  /

Type created.

SQL> create or replace function to_string(p_array in string_array) return varchar2
  2  as
  3     l_string varchar2(32767);
  4     i binary_integer;
  5  begin
  6     i := p_array.first();
  7     while i is not null loop
  8        l_string := l_string || p_array(i) || ';';
  9        i := p_array.next(i);
 10     end loop;
 11     l_string := rtrim(l_string, ';');
 12     return l_string;
 13  end;
 14  /

Function created.

2）在java中

public class ArrayTest {
    public static void main(String[] args) throws SQLException {
        DriverManager.registerDriver(new OracleDriver());
        OracleConnection connection = (OracleConnection) DriverManager.getConnection(...);

        String[] elements = {"abc", "def", "geh"};
        ArrayDescriptor descriptor = ArrayDescriptor.createDescriptor("STRING_ARRAY", connection);
        ARRAY array = new ARRAY(descriptor, connection, elements);

        OracleCallableStatement stmt = (OracleCallableStatement) connection.prepareCall("{? = call to_string(?)}");
        stmt.registerOutParameter(1, Types.VARCHAR);
        stmt.setARRAY(2, array);
        stmt.execute();

        String result = stmt.getString(1);
        System.out.println("to_string returned: " + result);
    }
}

似乎有效：输出说

to_string returned: abc;def;geh

Answer 3

由于自{12}以来不推荐使用ArrayDescriptor，因此不应再使用它。这是在12c中为我工作的代码片段：

            Array array = ((OracleConnection) connection).createOracleArray("T_VARCHAR2_ARRAY", data);
            CallableStatement statement = connection.prepareCall("{call p_array_test(?)}");
            statement.setArray(1, array);
            statement.execute();

Answer 4

您可以使用Oracle Types将Java对象映射到Oracle。此外，还有Spring JDBC实用程序。

Answer 5

正则表达式解决

select * from table_a  a where a.col in (select   regexp_substr('SMITH,ALLEN,WARD,JONES','[^,]+', 1, level) from dual
connect by regexp_substr('SMITH,ALLEN,WARD,JONES', '[^,]+', 1, level) is not null;)

Answer 6

PeudoCode与我的实现方式相同。

    # 1.You will require a structDescriptor object for an object equivalent in pl sql like :

    StructDescriptor structDes= new StructDescriptor("<schemaname in caps>.<sql_object_name>", connectionObject);

    # 2. You will need to pass one object values such name, class, id to an object array in order and accordance to 'sql_object_name' object. 

    For exmaple:
    STRUCT[] structArray=new STRUCT[<ListObj>.size()];
    int index=0;
    for (a in ListObj){

    Object[] object=new Object[]{a.getName(),a.getId()};
    STRUCT struct=new STRUCT(structDes ,connectionObject,object);
               structArray[index]=struct;
               index++;

    }

    ArrayDescriptor arrayDes=ArrayDescriptor.createDescriptor(
        "<Schema name>.<table object from sql>", connectionObject);

    ARRAY array=new ARRAY(arrayDes,connectionObject, structArray);

   then pass it to proc 

   .declareParameters(
   new SqlInOutParameter("<parameter to proc name>",OracleTypes.ARRAY,"
   <schema name>.<sql_array_or_table_obj>"))

   like 
   Hashmap<String, Object> map= new HashMap<>();
   map.put("<parameter to proc name>",array);
   psStatement.execute(map);

希望它有所帮助。此序列可能根据所使用的sql数据库的要求和类型而有所不同，但基数相同。

我从其他一个答案中复制了这个答案。

Pass array as input parameter to an oracle stored procedure using simple jdbc call

将数组传递给oracle程序

6 个答案: