Question

我有一个学生数据库，我需要给每个家庭寄一封信，但地址上必须有姓氏。同一家庭中可能有多个姓氏，因此我需要分别提及每个姓氏，但仍只向该地址发送一封信。 SQL 2014。

样本数据：

    +------------+----------------+-------+-------+-------+
    |  LastName  |   Address 1    | City  | State |  Zip  |
    +------------+----------------+-------+-------+-------+
    |  Smith     | 123 Fake St.   |  NY   |  NY   | 12345 |
    |  Jones     | 123 Fake St.   |  NY   |  NY   | 12345 |
    |  Ball      | 123 North St.  |  NY   |  NY   | 12345 |
    |  Wood      | 123 South St.  |  NY   |  NY   | 12345 |
    |  Ball      | 123 South St.  |  NY   |  NY   | 12345 |
    +------------+----------------+-------+-------+-------+

我需要退货：

    +-------------------+----------------+-------+-------+-------+
    |  LastName         |   Address 1    | City  | State |  Zip  |
    +-------------------+----------------+-------+-------+-------+
    |  Smith & Jones    | 123 Fake St.   |  NY   |  NY   | 12345 |
    |  Ball             | 123 North St.  |  NY   |  NY   | 12345 |
    |  Wood & Ball      | 123 South St.  |  NY   |  NY   | 12345 |
    +-------------------+----------------+-------+-------+-------+

编辑-感谢@TanvirArjel，我使用了以下最终查询，该查询比我的原始帖子所建议的要复杂一些。希望这对其他人有帮助！

    SELECT STUFF((
        SELECT DISTINCT ',' + LastName
        FROM Users
        WHERE (
                CASE 
                    WHEN Student_MailUnitNumber IS NULL
                        THEN CONCAT (
                                Student_MailStreetNumber
                                ,' '
                                ,Student_MailStreetName
                                )
                    ELSE CONCAT (
                            Student_MailStreetNumber
                            ,' '
                            ,Student_MailStreetName
                            ,', '
                            ,Student_MailUnitNumber
                            )
                    END
                ) = a.Address1
            AND City = a.City
            AND [State] = a.[State]
            AND Zip = a.Zip
        FOR XML PATH('')
        ), 1, 1, '') AS LastName
,Address1
,City
,STATE
,Zip
    FROM (
SELECT LastName
    ,CASE 
        WHEN Student_MailUnitNumber IS NULL
            THEN CONCAT (
                    Student_MailStreetNumber
                    ,' '
                    ,Student_MailStreetName
                    )
        ELSE CONCAT (
                Student_MailStreetNumber
                ,' '
                ,Student_MailStreetName
                ,', '
                ,Student_MailUnitNumber
                )
        END AS [Address1]
    ,Student_MailCity AS [City]
    ,Student_MailState AS [State]
    ,Student_MailZip AS [Zip]
FROM users
WHERE usertype = 'Student'
    AND isActive = 1
    AND PriBuilding IS NOT NULL
    AND student_grade NOT LIKE '%K%'
    AND Student_Grade <> '1'
) AS A
    GROUP BY Address1
,City
,STATE
,Zip

Answer 1

尝试一下：

SELECT Address1,City,State,Zip,
     STUFF(
         (SELECT DISTINCT ',' + LastName
          FROM TableName
          WHERE Address1 = a.Address1 AND City= a.City AND State = a.State and Zip = a.Sip
          FOR XML PATH (''))
          , 1, 1, '')  AS LastName
FROM TableName AS a
GROUP BY Address1, City,State,Zip

SQL DISTINCT在除一列以外的多列上，合并结果中的最后一列

1 个答案: