Question

我对SQL还是很陌生，以下代码有问题：

SELECT
in_profiles.profiles AS IncludeProfiles
,no_profiles.profiles AS ExcludeProfiles
, data.*,

CASE
    WHEN data.travel_type NOT LIKE 'car' THEN data.reason_code <> 'PT' ELSE
END CASE

FROM transportation_data data

Answer 1

您可以使用where子句确定要返回的内容。在这种情况下，如此给定的汽车原因代码似乎无关紧要

Total - (OnesInCol[0] + OnesInCol[1] ), OnesInCol[0] + OnesInCol[1]

查询看起来像这样

int count = 0;
int prevOnes = 0;
int onesInRowAboveThisCut = 0;
for ( int i = 1; i < rows; i++ ) {
   onesInRowAboveThisCut = prevOnes + OnesInRow[i-1];
   if ( onesInRowAboveThisCut= total/2 ) count++;
   prevOnes = onesInRowAboveThisCut;
}
prevOnes = 0;
int onesInColBeforeThisCut = 0;
for ( int i = 1; i < cols; i++ ) {
   onesInColBeforeThisCut  = prevOnes + OnesInCol[i-1];
   if ( onesInColBeforeThisCut = total/2 ) count++;
   prevOnes = onesInColBeforeThisCut ;
}

return count;

结果

drop table if exists transportation_data;
create table transportation_data (travel_type varchar(10), reason_code varchar(3));
insert into transportation_data values
('car','pt'),('car','xx'),
('bus','pt'),('bus','xx');

或者可能是

SELECT data.*
FROM transportation_data data
where travel_type = 'car' or (travel_type <> 'car' and reason_code <>'pt')

取决于口味

选择除满足特定条件的列之外的所有内容

1 个答案: