我正在尝试从普通Groovy类内部运行sql代码(无服务)。 在Grails 2中,我可以通过执行以下操作访问数据源:
public GroovyClass() {
def ctx = ServletContextHolder.servletContext.getAttribute(GrailsApplicationAttributes.APPLICATION_CONTEXT)
def dataSource = ctx.getBean('dataSource')
sql = new Sql(dataSource)
}
迁移到Grails 3.3.8后,该代码不再起作用。 Grails 3.3.8中正确的方法是什么?
答案 0 :(得分:2)
“好莱坞原则”说:“不要打电话给我们,我们会打电话给您”,这就是依赖注入的含义。就您而言,不要去拿dataSource
,不要给dataSource
。
有很多方法可以做到这一点。参见位于https://github.com/jeffbrown/asdudemo的项目。
// src/main/groovy/ascudemo/FirstGroovyClass.groovy
package ascudemo.helpers
import groovy.sql.Sql
import groovy.util.logging.Slf4j
import org.springframework.beans.factory.InitializingBean
import javax.sql.DataSource
@Slf4j
class FirstGroovyClass implements InitializingBean {
DataSource dataSource
Sql sql
void logSomeInfo() {
// both have been initialized
log.debug "dataSource: ${dataSource}"
log.debug "sql: ${sql}"
}
@Override
void afterPropertiesSet() throws Exception {
sql = new Sql(dataSource)
}
}
// src/main/groovy/ascudemo/SecondGroovyClass.groovy
package ascudemo.helpers
import groovy.sql.Sql
import groovy.util.logging.Slf4j
import javax.annotation.PostConstruct
import javax.sql.DataSource
@Slf4j
class SecondGroovyClass {
DataSource dataSource
Sql sql
void logSomeInfo() {
// both have been initialized
log.debug "dataSource: ${dataSource}"
log.debug "sql: ${sql}"
}
@PostConstruct
void initSql() throws Exception {
sql = new Sql(dataSource)
}
}
// src/main/groovy/ascudemo/SecondGroovyClass.groovy
package ascudemo.helpers
import groovy.sql.Sql
import groovy.util.logging.Slf4j
import org.springframework.beans.BeansException
import org.springframework.context.ApplicationContext
import org.springframework.context.ApplicationContextAware
import javax.sql.DataSource
@Slf4j
class ThirdGroovyClass implements ApplicationContextAware {
Sql sql
void logSomeInfo() {
// sql been initialized
log.debug "sql: ${sql}"
}
@Override
void setApplicationContext(ApplicationContext applicationContext) throws BeansException {
DataSource dataSource = applicationContext.getBean('dataSource', DataSource)
sql = new Sql(dataSource)
}
}
// grails-app/controllers/ascudemo/DemoController.groovy
package ascudemo
class DemoController {
SomeService someService
def index() {
someService.logSomeInfo()
render 'Success'
}
}
https://github.com/jeffbrown/asdudemo/blob/master/grails-app/services/ascudemo/SomeService.groovy
// grails-app/services/ascudemo/SomeService.groovy
package ascudemo
import ascudemo.helpers.FirstGroovyClass
import ascudemo.helpers.SecondGroovyClass
import ascudemo.helpers.ThirdGroovyClass
class SomeService {
FirstGroovyClass firstGroovyBean
SecondGroovyClass secondGroovyBean
ThirdGroovyClass thirdGroovyBean
def logSomeInfo() {
firstGroovyBean.logSomeInfo()
secondGroovyBean.logSomeInfo()
thirdGroovyBean.logSomeInfo()
}
}
https://github.com/jeffbrown/asdudemo/blob/master/grails-app/conf/spring/resources.groovy
// grails-app/conf/spring/resources.groovy
import ascudemo.helpers.FirstGroovyClass
import ascudemo.helpers.SecondGroovyClass
import ascudemo.helpers.ThirdGroovyClass
beans = {
// demonstrates one approach
firstGroovyBean(FirstGroovyClass) { bean ->
bean.autowire = 'byName'
}
// demonstrates another approach
secondGroovyBean(SecondGroovyClass) { bean ->
bean.autowire = 'byName'
}
// demonstrates a third approach
thirdGroovyBean ThirdGroovyClass
}
运行该应用程序,然后向http://localhost:8080/demo/发送请求,这将验证所有3种方法是否都有效。
还有其他方法可以做到这一点,但我希望以上所述对您有所帮助。
祝你好运!
答案 1 :(得分:0)
我刚刚对此进行了测试,它似乎可以提供数据源
def ds = Holders.grailsApplication.mainContext.getBean('dataSource')
println "DataSource: ${ds}" ---> DataSource: org.springframework.jdbc.datasource.TransactionAwareDataSourceProxy@5e91ade8
没有尝试对其进行任何操作,但是看起来不错。