Question

我有一堆文件，在方括号中有其他信息。我想通过删除该部分来重命名它们。

例如：

function getCoordinate() {

 // Distict SQL Query for first loop 
     (SELECT DISTINCT(id_shipment) as id_shipment FROM tbl_tracking)

    $id_shipment = $this->Maps_model->getIdShipment(); 

 // First Loop
      foreach ($id_shipment as $value) {
          // The object i want to loop for views
          $json = array(
                    'type' => 'Feature',
                    'properties' => json_decode('{}'),
                    'geometry' => array(
                    'type' => 'LineString',
                    'coordinates' => array()
                  ));

 //Query for getting coordinate
   (SELECT a.latitude,a.latitude,b.ship_name from tbl_tracking a
    LEFT JOIN tbl_shipment b on a.id_shipment = b.id
    WHERE a.id_shipment = $value['id_shipment']);

      $coordinate = $this->Maps_model->getCoordinate($value['id_shipment']);

 //Second Loop inside The First Loop
        foreach ($coordinate as $key) {
          $json['geometry']['coordinates'] = array (  
                (float)$key['latitude'],
                (float)$key['longitude']
          );
        }
    echo json_encode($json);
    }
}

想重命名为：

filename [additional info 1].ext1
anotherfile [different info 2].ext2

我尝试使用正则表达式（并使用重命名命令），但没有成功。有人知道一种只包含“ [....]”部分（包括前导空格）的重命名命令条的方法。

Answer 1

为每个文件循环并使用sed进行一些简单的正则表达式匹配：

for i in *.ext*; do 
    mv "$i" "$(sed 's/ \[[^]]*\]\././' <<<"$i")"
done

经过测试：

$ touch 'filename [additional info 1].ext1' 'filename [additional info 2].ext2'
$ for i in *.ext*; do mv -v "$i" "$(sed 's/ \[[^]]*\]\././' <<<"$i")"; done
renamed 'filename [additional info 1].ext1' -> 'filename.ext1'
renamed 'filename [additional info 2].ext2' -> 'filename.ext2'

使用正则表达式重命名文件名的一部分

1 个答案: