在其他示例中，我看到它与我的相似，有一个根节点，然后是一个数组节点，然后是一堆数组项。我的问题是，我的根节点是我的数组节点，所以我看到的示例似乎对我不起作用，我无法更改XML模式。这是XML：
<articles>
<article>
<guid>7f6da9df-1a91-4e20-8b66-07ac7548dc47</guid>
<order>1</order>
<type>deal_abstract</type>
<textType></textType>
<id></id>
<title>Abu Dhabi's IPIC Eyes Bond Sale After Cepsa Buy</title>
<summary>Abu Dhabi's IPIC has appointed banks for a potential sterling and euro-denominated bond issue, a document showed on Wednesday, after the firm acquired Spain's Cepsa in a $5 billion deal earlier this month...</summary>
<readmore></readmore>
<fileName></fileName>
<articleDate>02/24/2011 00:00:00 AM</articleDate>
<articleDateType></articleDateType>
</article>
<article>
<guid>1c3e57a0-c471-425a-87dd-051e69ecb7c5</guid>
<order>2</order>
<type>deal_abstract</type>
<textType></textType>
<id></id>
<title>Big Law Abuzz Over New China Security Review</title>
<summary>China’s newly established foreign investment M&A review committee has been the subject of much legal chatter in the Middle Kingdom and beyond. Earlier this month, the State Council unveiled legislative guidance on…</summary>
<readmore></readmore>
<fileName></fileName>
<articleDate>02/23/2011 00:00:00 AM</articleDate>
<articleDateType></articleDateType>
</article>
</articles>
这是我的班级：
public class CurrentsResultsList
{
public Article[] Articles;
}
public class Article
{
public string Guid { get; set; }
public int Order { get; set; }
public string Type { get; set; }
public string Title { get; set; }
public string Summary { get; set; }
public DateTime ArticleDate { get; set; }
}
这是来自外部API的XML响应。
答案 0 :(得分：8)
现在你准备好了c＃class
现在你可以使用它：
internal class ParseXML
{
public static xsdClass ToClass<xsdClass>(XElement ResponseXML)
{
return deserialize<xsdClass>(ResponseXML.ToString(SaveOptions.DisableFormatting));
}
private static result deserialize<result>(string XML)
{
using (TextReader textReader = new StringReader(XML))
{
XmlSerializer xmlSerializer = new XmlSerializer(typeof(result));
return (result) xmlSerializer.Deserialize(textReader);
}
}
}
答案 1 :(得分：5)
你必须使用一些Xml属性，这个代码应该有希望产生你喜欢的xml，希望它有所帮助：
using System;
using System.IO;
using System.Xml.Serialization;
namespace xmlTest
{
class Program
{
static void Main(string[] args)
{
var articles = new Articles();
articles.ArticleArray = new ArticlesArticle[2]
{
new ArticlesArticle()
{
Guid = Guid.NewGuid(),
Order = 1,
Type = "deal_abstract",
Title = "Abu Dhabi...",
Summary = "Abu Dhabi...",
ArticleDate = new DateTime(2011,2,24)
},
new ArticlesArticle()
{
Guid = Guid.NewGuid(),
Order = 2,
Type = "deal_abstract",
Title = "Abu Dhabi...",
Summary = "China...",
ArticleDate = new DateTime(2011,2,23)
},
};
var sw = new StringWriter();
var xmlSer = new XmlSerializer(typeof (Articles));
var noNamespaces = new XmlSerializerNamespaces();
noNamespaces.Add("", "");
xmlSer.Serialize(sw, articles,noNamespaces);
Console.WriteLine(sw.ToString());
}
}
[XmlRoot(ElementName = "articles", Namespace = "", IsNullable = false)]
public class Articles
{
[XmlElement("article")]
public ArticlesArticle[] ArticleArray { get; set; }
}
public class ArticlesArticle
{
[XmlElement("guid")]
public Guid Guid { get; set; }
[XmlElement("order")]
public int Order { get; set; }
[XmlElement("type")]
public string Type { get; set; }
[XmlElement("textType")]
public string TextType { get; set; }
[XmlElement("id")]
public int Id { get; set; }
[XmlElement("title")]
public string Title { get; set; }
[XmlElement("summary")]
public string Summary { get; set; }
[XmlElement("readmore")]
public string Readmore { get; set; }
[XmlElement("fileName")]
public string FileName { get; set; }
[XmlElement("articleDate")]
public DateTime ArticleDate { get; set; }
[XmlElement("articleDateType")]
public string ArticleDateType { get; set; }
}
}
答案 2 :(得分：3)
我能想到的最简单的方法可能就是使用xsd工具。你给它XML，它将从中生成一个模式。您可能需要稍微调整一下架构，但它应该很接近。
从那里，你可以通过xsd发回相同的模式，从中生成类。
答案 3 :(得分：2)
>xsd test.xml Microsoft (R) Xml Schemas/DataTypes support utility [Microsoft (R) .NET Framework, Version 4.0.30319.1] Copyright (C) Microsoft Corporation. All rights reserved. Writing file 'test.xsd'. >xsd /c test.xsd Microsoft (R) Xml Schemas/DataTypes support utility [Microsoft (R) .NET Framework, Version 4.0.30319.1] Copyright (C) Microsoft Corporation. All rights reserved. Writing file 'test.cs'.
结果：
//------------------------------------------------------------------------------
// <auto-generated>
// This code was generated by a tool.
// Runtime Version:4.0.30319.1
//
// Changes to this file may cause incorrect behavior and will be lost if
// the code is regenerated.
// </auto-generated>
//------------------------------------------------------------------------------
using System.Xml.Serialization;
//
// This source code was auto-generated by xsd, Version=4.0.30319.1.
//
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)]
public partial class articles {
private articlesArticle[] itemsField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("article", Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public articlesArticle[] Items {
get {
return this.itemsField;
}
set {
this.itemsField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)]
public partial class articlesArticle {
private string guidField;
private string orderField;
private string typeField;
private string textTypeField;
private string idField;
private string titleField;
private string summaryField;
private string readmoreField;
private string fileNameField;
private string articleDateField;
private string articleDateTypeField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string guid {
get {
return this.guidField;
}
set {
this.guidField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string order {
get {
return this.orderField;
}
set {
this.orderField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string type {
get {
return this.typeField;
}
set {
this.typeField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string textType {
get {
return this.textTypeField;
}
set {
this.textTypeField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string id {
get {
return this.idField;
}
set {
this.idField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string title {
get {
return this.titleField;
}
set {
this.titleField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string summary {
get {
return this.summaryField;
}
set {
this.summaryField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string readmore {
get {
return this.readmoreField;
}
set {
this.readmoreField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string fileName {
get {
return this.fileNameField;
}
set {
this.fileNameField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string articleDate {
get {
return this.articleDateField;
}
set {
this.articleDateField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)]
public string articleDateType {
get {
return this.articleDateTypeField;
}
set {
this.articleDateTypeField = value;
}
}
}