Laravel queryBuilder(5.6)

时间:2018-08-23 07:44:15

标签: php sql laravel laravel-query-builder

您好,我正在尝试将此SQL代码复制到Laravel qBuilder中,但没有在集合中得到想要的结果:

select chars.name, class.name, specs.name
FROM characters as chars 
JOIN charclasses as class
JOIN charspecs as specs
WHERE chars.class_id = class.id
AND chars.spec_id = specs.id

我得到以下输出:
enter image description here

然后我在Laravel中尝试了此操作

$charData = DB::table('characters')
        ->select('characters.*', 'charclasses.name', 'charspecs.name')
        ->join('charclasses', 'characters.class_id', '=', 'charclasses.id')
        ->join('charspecs', 'characters.spec_id', '=', 'charspecs.id')
        ->orderBy('user_id', 'ASC')
        ->get();
    dd($charData);

,结果是:
enter image description here

1 个答案:

答案 0 :(得分:1)

问题是您要选择三个具有相同名称的字段。这些字段在php代码中添加到了一个数组中,但是该数组字段被覆盖了两次,因为关联数组中没有重复的键。如果要选择三个名称,则必须给它们起另一个名称。

$charData = DB::table('characters')
    ->select('characters.*', 'charclasses.name as charclassname', 'charspecs.name as charspecname')
    ->join('charclasses', 'characters.class_id', '=', 'charclasses.id')
    ->join('charspecs', 'characters.spec_id', '=', 'charspecs.id')
    ->orderBy('user_id', 'ASC')
    ->get();
dd($charData);