Question

我有一个像这样的数据集。

ID        EQP_ID         DATE           ENTRY     EXIT
10        1232           10/01/2018     0058      NA
10        8123           10/01/2018     NA        0059
11        8231           10/02/2018     0063      NA
11        233            10/03/2018     0064      NA
11        2512           10/04/2018     NA        0099
11        2111           10/05/2018     NA        1000

我想折叠观察值，以便将给定ID带有“ ENTRY”的最早行与具有EXIT值的最新行合并，并且我还获得与退出记录相关联的EQP_ID：

ID       EQP_ID    ENTRY       EXIT
10       8123      0058        0059
11       2111      0063        1000

我对R还是很陌生，这非常复杂，以至于我想不出一个不求助于循环的好方法，而且性能也不是很好。

修改

我想这样做，但是我仍然很好奇其他经验丰富的人是否有更好的答案

> group_by(dataset, ID) %>% 
  arrange(ENTRY) %>% 
  summarize(ENTRY = first(ENTRY), EXIT = last(exit), EQP_ID = last(EQP_ID))

Answer 1

带有data.table的一个选项：

library(data.table)

#create example data
dt <- data.table(
    id = c(10, 10, 11, 11, 11, 11),
    date = seq(as.Date("2018-10-1"), as.Date("2018-10-6"), by="day"),
    entry = c(58, NA, 63, 64, NA, NA),
    exit = c(NA, 59, NA, NA, 99, 100)
)

# number rows by id
dt[order(id, date), num := 1:.N, by=id]

# get first-entry and last-exit values by id
dt[ , keepentry := entry[1],by=id]
dt[ , keepexit  := exit[.N],by=id]

# keep one row per id
dt[num==1, .(id, keepentry, keepexit)]

这不是我最优雅的工作，但可以完成工作。

Answer 2

使用PLAY [Print variables defined earlier] ************************************************************************* TASK [debug] ************************************************************************* ok: [192.168.1.13] => (item=None) => { "hostvars[\"192.168.1.12\"]['temp_file']['path']": "/tmp/ansible.DZIGlA" }和Sub AddTriangleShape() Dim osld As slide Dim oSh As Shape Dim oEffect As Effect ReDim ShapesToDelete(0) Dim ShapeCount For Each osld In ActivePresentation.Slides If osld.SlideShowTransition.Hidden Then Else For Each oSh In osld.Shapes If oSh.Name Like "@END@" Then ShapeCount = ShapeCount + 1 ReDim Preserve ShapesToDelete(0 To ShapeCount) Set ShapesToDelete(ShapeCount) = oSh End If Next oSh End If Next osld For i = 1 To ShapeCount ShapesToDelete(i).Delete Next For Each osld In ActivePresentation.Slides If osld.SlideShowTransition.Hidden Then Else Set oSh = osld.Shapes.AddShape(msoShapeRightTriangle, 947, 529, 6, 6) With oSh .Line.ForeColor.RGB = RGB(0, 0, 255) .Fill.Visible = msoTrue .Fill.ForeColor.RGB = RGB(0, 0, 255) .BlackWhiteMode = msoBlackWhiteDontShow .Flip (msoFlipHorizontal) .Name = "@END@" End With Set oEffect = osld.TimeLine.MainSequence.AddEffect _ (Shape:=oSh, effectid:=msoAnimEffectDissolve, trigger:=msoAnimTriggerAfterPrevious, Index:=-1) End If Next osld End Sub，我们可以执行以下操作；可以使用dplyr::first和dplyr::last

min

Answer 3

此解决方案使用dplyr。首先，定义数据框。

df <- read.table(text = "ID        EQP_ID         DATE           ENTRY     EXIT
10        1232           10/01/2018     0058      NA
10        8123           10/01/2018     NA        0059
11        8231           10/02/2018     0063      NA
11        233            10/03/2018     0064      NA
11        2512           10/04/2018     NA        0099
11        2111           10/05/2018     NA        1000", header = TRUE)

接下来，按ID分组，并分别使用head或tail取得该组中变量的第一个或最后一个值。

df %>% 
  group_by(ID) %>% 
  summarise(EQP_ID = tail(EQP_ID, 1),
            ENTRY = head(ENTRY, 1),
            EXIT = tail(EXIT, 1))

这给了

# # A tibble: 2 x 4
#       ID EQP_ID ENTRY  EXIT
#    <int>  <int> <int> <int>
# 1    10   8123    58    59
# 2    11   2111    63  1000

根据R中的第一个和最后一个出现折叠观察行

3 个答案: