Question

这是我下面的代码。我想显示“通过”或“失败”作为该特定建筑物/物业/公寓大楼的“无家可归”字段的值。下面的代码返回这些行：

Property   Homeless
1523cdc    Fail
1523cdc    Pass
2700       Fail
2700       Fail

在名为 2700 的建筑物中，有8个公寓，其中7个被标记为“无家可归”字段，其中1个公寓为空白。在名为 1523cdc 的建筑物中，有6个apts，其中1个被标记为“无家可归”字段为“是”，其余5个为空白。我正在尝试跟踪他标记为“无家可归”的公寓的百分比-2700应该是100％，1523cdc应该是16.6666％。 我只想为每栋建筑物设置一行，在此示例中，它应该是2700 Fail和1523cdc Pass

我该怎么做。谢谢：|

 SELECT  p.sCode "Property"
, case when (sum(case when p.scode = '2700' and unit.sfield5 = 'yes' then 1 else 0 end)) = 8 then 'Pass'
       when (sum(case when p.scode = '1523cdc' and unit.sfield5 = 'yes' then 1 else 0 end)) = 1      
       then 'Pass' else 'Fail' end as 'Homeless'
 FROM  Property p  left JOIN Unit ON (p.hMy = unit.hProperty) 
 WHERE 1 = 1
 and unit.scode not like ('b%')
 and unit.scode not like ('h%')
 and unit.scode not like ('s%')
 and unit.scode != 'HOMESPUN'
 and p.scode in ('2700','1523cdc')
 group by p.scode, unit.sfield5
 ORDER BY  p.sCode ASC

Answer 1

2件事：

您不需要1=1

您不应该group by unit.sfield5-由于您有2个值（是和空白），因此会产生2行

SELECT  p.sCode "Property"
    , case when (sum(case when p.scode = '2700' and unit.sfield5 = 'yes' then 1 else 0 end)) = 8 then 'Pass'
           when (sum(case when p.scode = '1523cdc' and unit.sfield5 = 'yes' then 1 else 0 end)) = 1      
           then 'Pass' else 'Fail' end as 'Homeless'
 FROM  Property p  left JOIN Unit ON (p.hMy = unit.hProperty) 
 WHERE unit.scode not like ('b%')
 and unit.scode not like ('h%')
 and unit.scode not like ('s%')
 and unit.scode != 'HOMESPUN'
 and p.scode in ('2700','1523cdc')
 group by p.scode
 ORDER BY p.sCode ASC

我的情况逻辑是，当至少存在两个不同的值时，返回两行

1 个答案: