Question

如何从此类的枚举中访问类的属性？

但是一旦实例化多个MyClass，所有实例的_toggledOn都是相同的。

我希望有一些我不知道的干净快捷的解决方法。无论如何要先谢谢你！

@IBDesignable
class MyClass: UIView, SomeProtocols {

    // MARK: - ENUM
    enum ToggleState {
        case on
        case off

        var color: UIColor {
            switch self {
            case .on:
                return _onColor
            default:
                return _offColor
            }
        }
    }

    // MARK: - STATICS
    private static var _onColor: UIColor = #colorliteral
    private static var _offColor: UIColor = #colorliteral

    // MARK: - IBSTUFF
    @IBInspectable var toggledOffColor: UIColor = #colorliteral {
        didSet {
            MyClass._offColor = toggledOffColor
            updateUI()
        }
    }

    @IBInspectable var toggledOnColor: UIColor = #colorliteral {
        didSet {
            MyClass._onColor = toggledOnColor
            updateUI()
        }
    }

    @IBOutlet weak var background: UIView!

    @IBAction func buttonPressed(_ sender: UIButton) {
        toggleState = toggleState == .off ? .on : .off
    }

    // MARK: - PROPERTIES
    var toggleState: ToggleState = .off {
        didSet { toggle() }
    }


    // MARK: - METHODS
    func updateUI() {
        background.backgroundColor = toggleState.color
        background.layer.addShadow()
    }

    func toggle() {
        background.backgroundColor = toggleState.color
    }
}

Answer 1

您的//our root app component import { Component, NgModule, VERSION } from '@angular/core'; import { BrowserModule } from '@angular/platform-browser'; import { FormsModule } from '@angular/forms'; @Component({ selector: 'my-app', template: ` <form #form="ngForm" class="edit-path__form"> <div class="edit-path__form-container"> <div class="grey-value-bold"></div> <div class="edit-path__form-sctypes"> <div *ngFor="let scProfile of Profiles; let rowIndex = index" class="path-template" > <label class="grey-title" style="flex-grow: 1;margin-left: 15px;" for="checkbox_{{rowIndex}}">{{scProfile.Name}}</label> <div class="checkbox" style="border-bottom: 1px solid;"> <input type="checkbox" id="checkbox_{{rowIndex}}" checked="{{scProfile.Enabled=== 'false'? null:''}}" name="{{scProfile.ID}}" > <label for="checkbox_{{rowIndex}}" style="float: left; margin-left: -20px;"></label> </div> </div> </div> </div> </form> `, }) export class App { name: string; Profiles: any; constructor() { this.name = `Angular! v${VERSION.full}`; this.Profiles = [ {Name: 'Alpha', ID: '1', Enabled: false}, {Name: 'Beta', ID: '2', Enabled: false}, {Name: 'Gamma', ID: '3', Enabled: false}, {Name: 'Delta', ID: '4', Enabled: false}, {Name: 'Zeta', ID: '5', Enabled: false}, {Name: 'Rho', ID: '6', Enabled: false} ] } } @NgModule({ imports: [BrowserModule, FormsModule], declarations: [App], bootstrap: [App], }) export class AppModule {}和<TextBox x: Name = "txt_Name" Header = "Name:" Margin = "5" Text = "{Binding NamePlacta, Mode = TwoWay}" IsEnabled = "True" />是静态的，因此对于您的类的每个实例，没有单独的_onColor和_offColor。\

您应将_onColor和_offColor设为非静态，并删除_onColor的{{1}}属性，而应在您的 class < / em>：

_offColor

您应该输入：
，而不是color。
ToggleState

func color(forToggleState state: ToggleState) { switch state { case .on: return _onColor case .off: return _offColor } }不应是toggleState.color的属性，因为要进行计算，您需要来自另一个对象的信息。

如何访问枚举之外的属性

1 个答案: