Question

我有一个在这里以某种方式讨论过的问题（[python][selenium] on-screen position of element），但是目前还没有达到我想要达到的目的。

我的目标是： element.location给出元素在浏览器中的左上角的位置。我有一个网站，即使它可能不是很好的硒实践，我也希望能够纯粹根据其位置单击该元素，因为它从未改变过，而且可能永远也不会改变。假设element.location给出{'x'：253，'y'：584}，这是我到目前为止尝试的没有运气的代码

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver.maximize_window()
url = "https://learn.letskodeit.com/p/practice"
driver.get(url)
open_window_elem = driver.find_element_by_id("openwindow")

# from wherever the mouse is, I move to the top left corner of the broswer
action = ActionChains(driver)
action.move_by_offset(-1000, -1000)    
action.click()
action.perform()

y_coordinate = open_window_elem.location["y"]
x_coordinate = open_window_elem.location["x"]

action = ActionChains(driver)
action.move_by_offset(x_coordinate, y_coordinate)
action.click()
action.perform()

当我运行此代码时，什么都没有发生。除了打开一个新窗口外，我只会。有人可以帮忙吗？

Answer 1

最好在元素的中间单击，而不是在其角落单击。有时无法点击角点。 “ openwindow”元素的坐标x和y是其左上角的坐标。

我建议计算元素中心的坐标。为此，请首先检查元素的宽度和高度：

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver.maximize_window()
url = "https://learn.letskodeit.com/p/practice"
driver.get(url)

open_window_elem = "//button[@id='openwindow']"

x = int(driver.find_element_by_xpath(open_window_elem).location['x'])
y = int(driver.find_element_by_xpath(open_window_elem).location['y'])
width = int(driver.find_element_by_xpath(open_window_elem).size['width'])
height = int(driver.find_element_by_xpath(open_window_elem).size['height'])

action = webdriver.common.action_chains.ActionChains(driver)
action.move_by_offset(x + width/2, y + height/2)
action.click()
action.perform()

Answer 2

尝试一下：

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver.maximize_window()
url = "https://learn.letskodeit.com/p/practice"
driver.get(url)
open_window_elem = driver.find_element_by_id("openwindow")

# from wherever the mouse is, I move to the top left corner of the broswer
action = ActionChains(driver)
action.move_by_offset(-1000, -1000)    
action.click().perform()

y_coordinate = open_window_elem.location["y"]
x_coordinate = open_window_elem.location["x"]

action = ActionChains(driver)
action.move_by_offset(int(x_coordinate), int(y_coordinate))
action.click().perform()

Answer 3

这是一个解决方案，基于（Clicking at coordinates without identifying element）上的最后一个答案，由于我的原始代码中发布的网站不起作用，我不得不对其进行调整：

# WORKING EXAMPLE 3
# assumptions is I know what coordinate I want to use
# in this example we use x = 253, y = 584
# remember: y = 584 -> it will move down  (a negative value moves up)
zero_elem = driver.find_element_by_tag_name('body')
x_body_offset = zero_elem.location["x"]
y_body_offset = zero_elem.location["y"]
print("Body coordinates: {}, {}".format(x_body_offset, y_body_offset))

x = 253
y = 310

actions = ActionChains(driver)
actions.move_to_element_with_offset(driver.find_element_by_tag_name('body'), -x_body_offset, -y_body_offset).click()
actions.move_by_offset( x, y ).click().perform()

基本上，身体坐标不一定是0,0，这就是为什么我不得不使用x_body_offset和y_body_offset。

Python Selenium-仅基于元素位置（基于主体元素偏移量）单击元素

3 个答案: