Question

我正在尝试使用第一个下拉菜单的数据来填充第二个下拉菜单。这里的一个例子： https://gitlab.com/Bons/laravel5.3_dynamic_dropdown/blob/master/readme.md

控制器功能返回数据，但第二个下拉列表为空。

第一个下拉列表：

<span>Country: </span>
<select style="width: 200px" class="country" id="id_country">
    <option value="0" disabled="true" selected="true">-Select-</option>
    @foreach($countries as $contry)
        <option value="{{$contry->id_country}}">{{$contry->name}}</option>
    @endforeach
</select>

链接的下拉列表：

  <label>City
        <select id="region" class="form-control input-sm" name="region_id">
            <option value=""></option>
        </select>
    </label>

脚本：

   <script type="text/javascript">
        $(document).ready(function(){
            $(document).on('change','.country',function(){
                console.log("hmm its change");
                var id=$(this).val();
                console.log(id)
                $.ajax({
                    type:'get',
                    url:'{!!URL::to('findRegions')!!}',
                    data:{'id':id},
                    success:function(data) {
                        console.log("success");
                        console.log(data.length);
                        console.log(data);
                        $.each(data, function(index,subCatObj){
                        //    console.log(subCatObj.name)
                            $('#region').append(''+subCatObj.name+'');
                        });
                    },
                    error:function(){
                        console.log("error");
                    }
                });
            });  
        });  
    </script>

路线：

Route::get('/findRegions/','GirlsController@findRegions');

控制器功能：

public function findRegions(Request $request){
    $id=$request->id;
    $regions=Region::select('name')
        ->where('id_country',$id)
        ->get();
  dump($regions);
  return $regions;
}

Answer 1

这是我的做法，在routes / web.php中

2018-08-16 15:04:17

在Controller中：Main.php

Route::post('select-ajax', 'Main@selectAjax')->name('select-ajax');

然后创建一个简单的刀片文件名称ajax-select.blade.php

public function __construct()
{
    View::share('selectAllCountries', Country::pluck("name","id")->all());
}
public function selectAjax(Request $request)
{
        if($request->ajax())
        {
            $getRegion = Region::where('id_country',$request->id)->pluck("nameOfTheRegion","id")->all();
            $data = view('ajax-select',compact('getRegion'))->render();
            return response()->json(['options'=>$data]);
        }
 }

Ajax调用

<option selected disabled>--- Select Region---</option>
@if(!empty($getRegion))
    @foreach($getRegion as $key => $value)
        <option value="{{ $key }}">{{ $value }}</option>
    @endforeach
@endif

希望这会有所帮助

Laravel 5 Multi Dynamic Dropdown

1 个答案: