Question

我有一个JSON，看起来像：

[{
    "lat": 43.96063343238712,
    "panoid": "sffcNG69c2kdZwEuYp1htw",
    "lon": 3.098330084924494
}, {
    "lat": 43.96052745649745,
    "panoid": "2rJPv_r0gC5FBPLZK5vHDA",
    "lon": 3.098487422195691
} and so on... ]

我要为每个元素（表示成对的括号）添加一个等于的键calc

(value of "lat") - 50

我该如何更新我的JSON？我想我应该将JSON转换为dictionary。但是之后如何进行？

Answer 1

使用json模块将字符串加载到列表中。遍历列表中的字典，并将属性{ "isExistsUnder": null, "State": "", "Value": "CustomElements", "Parts": [ { "isExistsUnder": null, "State": 0, "Value": "Rule 73", "Parts": [ { "isExistsUnder": null, "State": "", "Value": "For variable initializations", "Parts": [ { "isExistsUnder": null, "State": "", "Value": "cupis", "Parts": [ { "isExistsUnder": null, "State":"", "Value": "randomText1", "Parts": [] }, { "isExistsUnder": null, "State":"", "Value": "randomText2", "Parts": [] }, { "isExistsUnder": null, "State":"", "Value": "randomText3", "Parts": [] } ] } } } }设置为calc值减去lat。

最后，如果需要，将列表转储到带有可选50 arg的字符串中以进行漂亮的打印。

indent

给予：

import json
s = '''[{
    "lat": 43.96063343238712,
    "panoid": "sffcNG69c2kdZwEuYp1htw",
    "lon": 3.098330084924494
}, {
    "lat": 43.96052745649745,
    "panoid": "2rJPv_r0gC5FBPLZK5vHDA",
    "lon": 3.098487422195691
}]'''
l = json.loads(s)
for d in l:
    d['calc'] = d['lat'] - 50
print(json.dumps(l, indent=4))

将新的计算值插入到Json中

1 个答案: