Question

我有这个查询：

SELECT agent, prezent, pobs, pobsextins 
FROM `raport` 
WHERE agent="agent1" and (pobs="da" || prezent="da" || pobsextins="da")

它返回：

agent   prezent pobs    pobsextins
agent1  NU      NU      DA
agent1  NU      NU      DA
agent1  NU      DA      DA
agent1  DA      NU      DA

我必须编写什么查询来自动计算所有行中的“ DA”并将其按代理分组？

我尝试过：

SELECT agent, prezent, pobs, pobsextins, COUNT(prezent), COUNT(pobs), COUNT(pobsextins) 
FROM `raport` 
WHERE agent="agent1" and (pobs="da" || prezent="da" || pobsextins="da")

但是我发现它只计算该列存在多少次。如果我尝试... COUNT(prezent) WHERE prezent="da", COUNT(pobs) WHERE... 给出错误

Answer 1

您可以对个案和分组依据

select agent
      ,sum(case when prezent = 'DA' then 1 else 0 end ) + 
       sum(case when pobs = 'DA' then 1 else 0 end ) + 
       sum(case when pobsextins = 'DA' then 1 else 0 end )  total  
from my_table 
group by  agent

Answer 2

您可以使用并集和分组依据。希望它对您有用。

select agent,count(*) from
 (select agent from `raport` where pobs="da"
  union all 
  select agent from `raport` where prezent="da"
  union all 
  select agent from `raport` where pobsextins="da") myReport
group by agent;

Find the Output here

计算不同列中的一个单词

2 个答案: