Question

在科特林，我把一个句子分成单词。 split方法在列表末尾添加一个空格。如何摆脱尾随的空间？有没有创建新列表的简单方法？

package com.zetcode

fun main(args: Array<String>) {

    val text = "I saw a fox in the wood. The fox had red fur."

    val pattern = "\\W+".toRegex()

    val words = pattern.split(text)

    println(words)
}

该示例显示[I, saw, a, fox, in, the, wood, The, fox, had, red, fur, ]

Answer 1

此处显示空项，因为您的字符串末尾有一个非单词infoLabel char。您可能只是省略了空项目以解决问题：

或者，使用与val text = "I saw a fox in the wood. The fox had red fur." val pattern = """\W+""".toRegex() val words = pattern.split(text).filter { it.isNotBlank() } println(words) // => [I, saw, a, fox, in, the, wood, The, fox, had, red, fur]相反的模式的匹配方法：

\w+

Answer 2

您可以删除最后一项：

val words = pattern.split(text).dropLastWhile { it == "" }

Kotlin正则表达式拆分-删除尾部空间

2 个答案: