Question

def strategy(board):
    import random
    #t_1 =, t_2 and t_3 are ranges from 0 to a object named board
    t_1 = [board[0] - i for i in range (0,(board[0] + 1))]
    t_2 = [board[1] - i for i in range (0,(board[1] + 1))]
    t_3 = [board[2] - i for i in range (0,(board[2] + 1))]

    #randomly chooses a single number from each range
    x = random.choice (t_1)
    y = random.choice (t_2)
    z = random.choice (t_3)

    #randomly chooses one of those 3 randomly chosen numbers
    q = random.choice (x,y,z)

如您所见，代码从3个不同范围中随机选择一个数字，并将每个数字分配给一个不同的变量。完成此操作后，它将从先前选择的3个数字中随机选择一个，并为其分配一个新变量。我不断收到标题中提到的错误。我不知道怎么了。谢谢您的帮助 ps。我在PyCharm中使用python 3

Answer 1

random.choice接受列表作为参数，因此应为：

q = random.choice([x,y,z])

错误：choice（）接受2个位置参数，但给出了4个

1 个答案: