Question

这是第一本字典：

[{'ITEMNO': None}, {'ITEM_TYPE': None}, {'CASE_QYT': None}, {'MIN_MINMAX_QUANTITY': None}, {'MAX_MINMAX_QUANTITY': None}, {'ONHAND': None}, {'ONHAND_SUBINV': None}, {'LOCATOR': None}, {'ORGANIZATION_ID': None}, {'INVENTORY_ITEM_ID': None}, {'CREATION_DATA': None}, {'INVENTORY_ITEM_STATUS_CODE': None}]

此词典包含所有关键元素，其值为None。我有第二本词典，其中可能包含第一本词典中的所有关键元素，或者少于第一本词典中的所有关键元素，但具有相同的关键元素。我想比较这两个字典，如果键相同，则用第二个字典的value元素替换None的值。第二本字典如下：

[{'ITEM_TYPE': 'SPR_ITEM_CPR'}, {'MIN_MINMAX_QUANTITY': '2'}, {'MAX_MINMAX_QUANTITY': '3'}, {'ONHAND': '162'}, {'ONHAND_SUBINV': 'RSP-SPARES'}, {'LOCATOR': '.RJG005D'}, {'ORGANIZATION_ID': '300000002445681'}, {'INVENTORY_ITEM_ID': '100000001537040'}, {'CREATION_DATE': '01-08-17'}, {'INVENTORY_ITEM_FLAG': 'Y'}, {'INVENTORY_ITEM_STATUS_CODE': 'Active'}]

结果字典应如下所示：

[{'ITEMNO': None}, {'ITEM_TYPE': 'SPR_ITEM_CPR'}, {'CASE_QTY': None}, {'MIN_MINMAX_QUANTITY': '2'}, {'MAX_MINMAX_QUANTITY': '3'}, {'ONHAND': '162'}, {'ONHAND_SUBINV': 'RSP-SPARES'}, {'LOCATOR': '.RJG005D'}, {'ORGANIZATION_ID': '300000002445681'}, {'INVENTORY_ITEM_ID': '100000001537040'}, {'CREATION_DATE': '01-08-17'}, {'INVENTORY_ITEM_FLAG': 'Y'}, {'INVENTORY_ITEM_STATUS_CODE': 'Active'}]

Answer 1

原始字典分别为dict1和dict2，可以使用dict.get在一行中创建新字典，如下所示：

new_dict = {k: dict2.get(k, v) for k, v in dict1.items()}

或者，因为您知道dict1中的默认值为None，所以您可以使用以下键：

new_dict = {k: dict2.get(k, None) for k in dict1}

或者如果您不关心突变dict1：

dict1.update(dict2)

Answer 2

尝试将l2转换为字典，然后形成所需的输出。

例如：

l1 = [{'ITEMNO': None}, {'ITEM_TYPE': None}, {'CASE_QYT': None}, {'MIN_MINMAX_QUANTITY': None}, {'MAX_MINMAX_QUANTITY': None}, {'ONHAND': None}, {'ONHAND_SUBINV': None}, {'LOCATOR': None}, {'ORGANIZATION_ID': None}, {'INVENTORY_ITEM_ID': None}, {'CREATION_DATA': None}, {'INVENTORY_ITEM_STATUS_CODE': None}]
l2 = [{'ITEM_TYPE': 'SPR_ITEM_CPR'}, {'MIN_MINMAX_QUANTITY': '2'}, {'MAX_MINMAX_QUANTITY': '3'}, {'ONHAND': '162'}, {'ONHAND_SUBINV': 'RSP-SPARES'}, {'LOCATOR': '.RJG005D'}, {'ORGANIZATION_ID': '300000002445681'}, {'INVENTORY_ITEM_ID': '100000001537040'}, {'CREATION_DATE': '01-08-17'}, {'INVENTORY_ITEM_FLAG': 'Y'}, {'INVENTORY_ITEM_STATUS_CODE': 'Active'}]

check_val = dict((i.keys()[0], i.values()[0]) for i in l2)
result = [{i.keys()[0]: check_val.get(i.keys()[0])} for i in l1 ]
print(result)

Python3

check_val = dict((list(i.keys())[0], list(i.values())[0]) for i in l2)
result = [{list(i.keys())[0]: check_val.get(list(i.keys())[0])} for i in l1 ]

输出：

[{'ITEMNO': None},
 {'ITEM_TYPE': 'SPR_ITEM_CPR'},
 {'CASE_QYT': None},
 {'MIN_MINMAX_QUANTITY': '2'},
 {'MAX_MINMAX_QUANTITY': '3'},
 {'ONHAND': '162'},
 {'ONHAND_SUBINV': 'RSP-SPARES'},
 {'LOCATOR': '.RJG005D'},
 {'ORGANIZATION_ID': '300000002445681'},
 {'INVENTORY_ITEM_ID': '100000001537040'},
 {'CREATION_DATA': None},
 {'INVENTORY_ITEM_STATUS_CODE': 'Active'}]

Answer 3

如果您有两个字典分别为dict1（None个值）和dict2（有意义的值），则可以update dict1为：

dict1.update(dict2)

正如其他答案所指出的，请注意，您没有dict，有list个dict s，并且您需要先做出命令，您可以这样做：

a_var = [{1 : None}, {2 : 'b'}]
dict1 =  {x.keys()[0]: x.values()[0] for x in a_var}

一旦有了，

dict2 = {1 : 'a', 2 : 'bb', 3 : 'c'}
dict1.update(dict2)

print(dict1)

输出：

{1: 'a', 2: 'bb', 3: 'c'}

如何在python中比较两个字典并相应地替换值？

3 个答案: