Question

我正在尝试解析一个使用日期作为数组名称的JSON，因此它是可变的。如何使用Java / Spring做到这一点？

"Time Series (Daily)": {
    "2018-08-21": {
        "1. open": "106.9200",
        "2. high": "107.2500",
        "3. low": "106.8100",
        "4. close": "107.0650",
        "5. volume": "1156207"
    },
    "2018-08-20": {
        "1. open": "107.5100",
        "2. high": "107.9000",
        "3. low": "106.4800",
        "4. close": "106.8700",
        "5. volume": "17914201"
    },

要获取时间序列（每天），我正在使用：

@JsonProperty("Time Series (Daily)")
TimeSeries timeSeries;

但是使用TimeSeries对象做什么

@JsonProperty("2018-08-21")
Date date;

只会得到第一个吗？

Answer 1

通过编写自定义解串器找到了解决方案。

时间序列类：

@JsonDeserialize(using = AvTimeSeriesDeserializer.class)
public class AvTimeSeries {

        List<AvDay> avDays;

    public List<AvDay> getAvDays() {
        return avDays;
    }

    public void setAvDays(List<AvDay> avDays) {
        this.avDays = avDays;
    }

}

反序列化器：

public class AvTimeSeriesDeserializer extends StdDeserializer<AvTimeSeries> {

/**
 * 
 */
private static final long serialVersionUID = 1L;

public AvTimeSeriesDeserializer() {
    this(null);
}

public AvTimeSeriesDeserializer(Class<?> vc) {
    super(vc);
}

@Override
public AvTimeSeries deserialize(JsonParser jp, DeserializationContext ctxt)
        throws IOException, JsonProcessingException {

List<AvDay> avDays = new ArrayList<>();

    JsonNode node = jp.getCodec().readTree(jp);
    Iterator<Entry<String, JsonNode>> hello = node.fields();
    hello.forEachRemaining(nodeA -> {
        String date = nodeA.getKey();
        JsonNode kappes = nodeA.getValue();
        double open = kappes.get("1. open").asDouble();
        double high = kappes.get("2. high").asDouble();
        double low = kappes.get("3. low").asDouble();
        double close = kappes.get("4. close").asDouble();
        long volume = kappes.get("5. volume").asLong();
        AvDay avDay = new AvDay(date, open, high, low, close, volume);
        avDays.add(avDay);
    });

    AvTimeSeries result = new AvTimeSeries();
    result.setAvDays(avDays);
    return result;
}

}

这可能仍然可以进行优化，但是可以正常工作。

如何使用以可变日期作为数组名称的JSON-Java / Spring

1 个答案: