Question

如果我有以下代码示例

async def coro():
    # Cancelled error could be raised here
    await asyncio.sleep(1)
    # Or here
    await asyncio.shield(
        another_coro()
    )
    # Or here

async def wait_on_it(loop):
    f = loop.create_task(coro())
    # Pretend f may or may not happen, I just sleep in this example
    await asyncio.sleep(1)
    if not f.done():
        f.cancel() # Will raise CancelledError when some await finishes in coro()

如何确定受保护的任务是否实际运行？如果已执行屏蔽任务，则必须执行重要的逻辑。也许屏蔽该功能不是正确的方法？

Answer 1

public function text(User $user) { $messages = DB::table('messages') ->join('threads', function($join){ $join->on('messages.thread_id', '=', 'threads.id') ->where('threads.id', '=', $user->threads[0]->id); })->get(); return view('backend.pending_registrations.textform', compact('user', 'messages')); }可以通过修改从调用者接收到的可变对象，将信息传递给调用者：

coro()

由于class Ref: def __init__(self, **kwargs): self.__dict__.update(**kwargs) async def coro(run_ref): await asyncio.sleep(1) run_ref.ran_another_coro = True await asyncio.shield(another_coro()) async def wait_on_it(loop): run_ref = Ref(ran_another_coro=False) f = loop.create_task(coro(run_ref)) await asyncio.sleep(1) if not f.done(): f.cancel() if run_ref.ran_another_coro: # ... another_coro() was started无法暂停，因此如果asyncio.shield的真实值是wait_on_it，则可以保证run_ref.ran_another_coro已经启动。

检查异步屏蔽的协程是否运行

1 个答案: