Question

是否可以在我在网络视图上定义的屏幕的某些部分中启用/禁用触摸事件？

Answer 1

可以通过/** Instantiate the interface and set the context */ class WebAppInterface(private val mContext: Context) { /** Show a toast from the web page */ @JavascriptInterface fun showToast(toast: String) { Toast.makeText(mContext, toast, Toast.LENGTH_SHORT).show() } }在您的网页中定义您的操作，然后在您的android代码中触发一个Java方法

如here所述，定义了类似波纹管的接口：

webView

然后将其攻击到val webView: WebView = findViewById(R.id.webview) webView.addJavascriptInterface(WebAppInterface(this), "Android")

<input type="button" value="Say hello" onClick="showAndroidToast('Hello Android!')" />

<script type="text/javascript">
    function showAndroidToast(toast) {
        Android.showToast(toast);
    }
</script>

，您应该在网页中实现以下功能，并在需要时触发

{{1}}

Answer 2

实际上现在 webview 不支持触摸操作。但是有一些解决方法可用；我将用一个长按示例来展示它：我使用 Pointoption 因为我将获得元素的坐标并将其用于长按。

public void longpress(PointOption po) {
   //first you need to switch to native view
    driver.switchToNativeView();
    TouchAction action = new TouchAction((PerformsTouchActions) driver);
    action.longPress(po).waitAction(WaitOptions.waitOptions(Duration.ofSeconds(2)));
    action.release();
    action.perform();
    driver.switchToDefaultWebView();
}

为了得到我在methood下面设计的元素的坐标

public PointOption getElementLocation(WebElement element) {
    int elementLocationX;
    int elementLocationY;

    //get element location in webview
    elementLocationX = element.getLocation().getX();
    elementLocationY = element.getLocation().getY();

    //get the center location of the element
    int elementWidthCenter = element.getSize().getWidth() / 2;
    int elementHeightCenter = element.getSize().getHeight() / 2;
    int elementWidthCenterLocation = elementWidthCenter + elementLocationX;
    int elementHeightCenterLocation = elementHeightCenter + elementLocationY;

    //calculate the ratio between actual screen dimensions and webview dimensions
    float ratioWidth = device.getDeviceScreenWidth() / ((MobileDevice) device)
            .getWebViewWidth().intValue();
    float ratioHeight = device.getDeviceScreenHeight() / ((MobileDevice) device)
            .getWebViewHeight().intValue();

    //calculate the actual element location on the screen , if needed you can increase this value,for example i used 115 for one of my mobile devices.
    int offset = 0;  


    float elementCenterActualX = elementWidthCenterLocation * ratioWidth;
    float elementCenterActualY = (elementHeightCenterLocation * ratioHeight) + offset;
    float[] elementLocation = {elementCenterActualX, elementCenterActualY};

    int elementCoordinateX, elementCoordinateY;
    elementCoordinateX = (int) Math.round(elementCenterActualX);
    elementCoordinateY = (int) Math.round(elementCenterActualY);
    PointOption po = PointOption.point(elementCoordinateX, elementCoordinateY);
    return po;
}

现在你有一个 longpress(PointOption po) 和 getElementLocation(Webelement element) 方法来给你 po。现在一切准备就绪，您可以按如下方式使用它们..

longpress(getElementLocation(driver.findElement(By.id("the selector can be any of them(xpath,css,classname,id etc.)")));

Android：WebView触摸事件监听器

2 个答案: