返回给定架构的表中的行数

Question

鉴于TSQL中的方案，我想从数据库中返回各个表中存在的记录数

示例：架构= ABC，表= ABC.T1，ABC.T2，ABC.T3

查询的输出：

No of records  Table
 10             T1
 5              T2
 36             T3

Answer 1

如果不需要事务一致的行数，则可以查询DMV。对于大型表，这将比SELECT COUNT(*)快得多：

SELECT t.name, SUM(p.rows) AS row_count
FROM sys.tables AS t
JOIN sys.partitions AS p ON p.object_id = t.object_id AND p.index_id IN(0,1)
WHERE OBJECT_SCHEMA_NAME(t.object_id) = N'ABC'
GROUP BY t.name;

Answer 2

使用union all：

select count(*) as [# of records], 't1' as [Table]
from abc.t1
union all
select count(*), 't2'
from abc.t2
union all
select count(*), 't3'
from abc.t3;