Question

我发现此代码可以上传文件，并且可以正常工作。

<%@ page import = "java.io.*,java.util.*, javax.servlet.*" %>
<%@ page import = "javax.servlet.http.*" %>
<%@ page import = "org.apache.commons.fileupload.*" %>
<%@ page import = "org.apache.commons.fileupload.disk.*" %>
<%@ page import = "org.apache.commons.fileupload.servlet.*" %>
<%@ page import = "org.apache.commons.io.output.*" %>

<%
   File file ;
   int maxFileSize = 5000 * 1024;
   int maxMemSize = 5000 * 1024;
   ServletContext context = pageContext.getServletContext();
   String filePath = context.getInitParameter("file-upload2");

   // Verify the content type
   String contentType = request.getContentType();

   if ((contentType.indexOf("multipart/form-data") >= 0)) {
      DiskFileItemFactory factory = new DiskFileItemFactory();
      // maximum size that will be stored in memory
      factory.setSizeThreshold(maxMemSize);

      // Location to save data that is larger than maxMemSize.
      factory.setRepository(new File("c:\\temp"));

      // Create a new file upload handler
      ServletFileUpload upload = new ServletFileUpload(factory);

      // maximum file size to be uploaded.
      upload.setSizeMax( maxFileSize );

      try { 
         // Parse the request to get file items.
         List fileItems = upload.parseRequest(request);

         // Process the uploaded file items
         Iterator i = fileItems.iterator();

         out.println("<html>");
         out.println("<head>");
         out.println("<title>JSP File upload</title>");  
         out.println("</head>");
         out.println("<body>");

         while ( i.hasNext () ) {
            FileItem fi = (FileItem)i.next();
            if ( !fi.isFormField () ) {
               // Get the uploaded file parameters
               String fieldName = fi.getFieldName();
               String fileName = fi.getName();
               boolean isInMemory = fi.isInMemory();
               long sizeInBytes = fi.getSize();

               // Write the file
               if( fileName.lastIndexOf("\\") >= 0 ) {
                  file = new File( filePath + 
                  fileName.substring( fileName.lastIndexOf("\\"))) ;
               } else {
                  file = new File( filePath + 
                  fileName.substring(fileName.lastIndexOf("\\")+1)) ;
               }
               fi.write( file ) ;
               out.println("Uploaded Filename: " + filePath + 
               fileName + "<br>");
            }
         }
         out.println("</body>");
         out.println("</html>");
      } catch(Exception ex) {
         System.out.println(ex);
      }
   } else {
      out.println("<html>");
      out.println("<head>");
      out.println("<title>Servlet upload</title>");  
      out.println("</head>");
      out.println("<body>");
      out.println("<p>No file uploaded</p>"); 
      out.println("</body>");
      out.println("</html>");
   }
   response.sendRedirect("clientupload.html");
%>

XML文件

<context-param> 
   <description>Location to store uploaded file</description> 
   <param-name>file-upload2</param-name> 
   <param-value>
        C:\Users\saurabh\Documents\NetBeansProjects\Amber_try\web\image\card\
    </param-value>
</context-param>

我需要这样更改地址

Amber_try\web\image\card\

但是如果我这样做，它将无法正常工作，代码可以编译，但是什么也没得到上载到指定的文件夹。我应该如何更改此地址？

我需要在服务器上上传文件，这是我去年的项目。编程的新手，请非常解释。

我正在制作一个网站，该网站可以在某些服务器上上传并进行实时演示（因为购买域名很容易，并且可以获取更多的商标），但是当我将其上传到服务器上时，会出现错误。 / p>

谢谢。

在jsp的服务器上上传图像

0 个答案: