Question

我的Web服务使用此信息进行响应

[
    {
        "IdWeek": 18340,
        "DateInit": "2018-08-19T00:00:00",
        "DateEnd": "2018-08-25T00:00:00",
        "TotalDays": 7,
        "WeekNumber": "34",
        "WeekDescription": "Semana del: 19/08/2018 al: 25/08/2018",
        "Status": 0,
        "IdWeekAccuredInit": 0,
        "IdWeekAccuredEnd": 0,
        "DateAccuredInit": "0001-01-01T00:00:00",
        "DateAccuredEnd": "0001-01-01T00:00:00"
    },
    {
        "IdWeek": 18330,
        "DateInit": "2018-08-12T00:00:00",
        "DateEnd": "2018-08-18T00:00:00",
        "TotalDays": 7,
        "WeekNumber": "33",
        "WeekDescription": "Semana del: 12/08/2018 al: 18/08/2018",
        "Status": 0,
        "IdWeekAccuredInit": 0,
        "IdWeekAccuredEnd": 0,
        "DateAccuredInit": "0001-01-01T00:00:00",
        "DateAccuredEnd": "0001-01-01T00:00:00"
    },

我想将这些值保存在名为Week的对象类中，但是我的任务出错。

class Week : Decodable
{
    let IdWeek:String
    let DateInit:Date
    let DateEnd:Date
    let TotalDays:Int
    let WeekNumber:String
    let WeekDescription:String
    let Status:Int
    let IdWeekAccuredInit:Int
    let IdWeekAccuredEnd:Int
    let DateAccuredInit:Date
    let DateAccuredEnd:Date
}

DispatchQueue.main.sync(execute: {
    do
    {
        //let json = try JSONSerialization.jsonObject(with: data, options: JSONSerialization.ReadingOptions.mutableContainers) as AnyObject

        guard let weeks = try? JSONDecoder().decode(Week.self, from: data)
        else
        {
            print("Error: No puede decodificar en Weeks")
            return
        }

        for idWeek in weeks.IdWeek
        {
            print("idSemana:\(idWeek)")
        }

        print("Creando Objeto JSON")
        //print(json)
    }
    catch
    {
        print("El procesamiento del JSON tuvo un Error")
    }
})

Answer 1

您的JSON是一个数组，因此您需要：

guard let weeks = try? JSONDecoder().decode([Week.self], from: data)

另外，不要大写您的属性，Swift约定是使用驼峰式大小写。

我如何无法获取JSON Array Swift 4中的de Properties

1 个答案: