C ++析构函数按值删除指针函数

时间:2018-08-20 19:19:33

标签: c++

我有此代码:

class allShapes {
private:
    Shape ** _arr;
    int _size;
public:
    allShapes();
    ~allShapes();
    int getSize() const;
    void addShape(Shape * newShape);
    allShapes operator+(const allShapes & other) const;
}

allShapes::~allShapes()
{
    if (_arr != NULL)
    {
        for (int i = 0; i < getSize(); i++)
        {
            delete _arr[i];
            _arr[i] = NULL;
        }

        delete[] _arr;
        _arr = NULL;
    }
};


allShapes allShapes::operator+(const allShapes & other) const
{
    allShapes newallShapes;
    for (int i = 0; i < getSize(); i++)
    {
        newallShapes.addShape(_arr[i]);
    }

    for (int i = 0; i < other.getSize(); i++)
    {
        newallShapes.addShape(other._arr[i]);
    }

    return newallShapes;
}

我的主:

allShapes shapes;

Circle * c1 = new Circle(3, "myCircle");
Circle * c2 = new Circle(2, "yourCircle");

shapes.addShape(c1);
shapes.addShape(c2);

allShapes newshape = shapes + shapes;

我的项目有问题:

有一些背景知识:我有allShapes,其中包含其他一些类,例如Circle和Square等。

我的操作员+有问题,

它将在方法中创建newallShapes良好,但随后在最后一行中:return newallShapes; 它调用析构函数,然后删除指针 newall形状并破坏一切!

我如何将带有所有指针的新“ newallShape”发回主机?

0 个答案:

没有答案
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